payUmoney集成出现错误

Question

登录后，它生成了一个哈希值，但仍然给出错误“Some problem currened！try tain”。

PayUmoneySdkInitilizer.PaymentParam.Builder builder =
    new PayUmoneySdkInitilizer.PaymentParam.Builder();

builder.setAmount(10.0)
       .setTnxId("0nf7" + System.currentTimeMillis())
       .setPhone(<My phone>)
       .setProductName("product_name")
       .setFirstName(<My Name>)
       .setEmail(<My email>)
       .setsUrl("https://www.payumoney.com/mobileapp/payumoney/success.php")
       .setfUrl("https://www.payumoney.com/mobileapp/payumoney/failure.php")
       .setUdf1("").setUdf2("").setUdf3("").setUdf4("").setUdf5("")
       .setIsDebug(false)
       .setKey(<mykey>)
       .setMerchantId(<my debug merchant id>);

String tnxId="0nf7" + System.currentTimeMillis();
PayUmoneySdkInitilizer.PaymentParam paymentParam = builder.build();
String hashSequence = "<...>|"+tnxId+"|10.0|product_name|<My name>|<My email>|||||||||||salt";
String serverCalculatedHash= hashCal("SHA-512", hashSequence);
Toast.makeText(getApplicationContext(),
               serverCalculatedHash, Toast.LENGTH_SHORT).show();
paymentParam.setMerchantHash(serverCalculatedHash);
// calculateServerSideHashAndInitiatePayment(paymentParam);
PayUmoneySdkInitilizer.startPaymentActivityForResult(TrayActivity.this, paymentParam);

public static String hashCal(String type, String str) {
    byte[] hashseq = str.getBytes();
    StringBuffer hexString = new StringBuffer();
    try {
        MessageDigest algorithm = MessageDigest.getInstance(type);
        algorithm.reset();
        algorithm.update(hashseq);
        byte messageDigest[] = algorithm.digest();
        for (int i = 0; i<messageDigest.length; i++) {
            String hex = Integer.toHexString(0xFF &messageDigest[i]);
            if (hex.length() == 1) { hexString.append("0"); }
            hexString.append(hex);
        }
    } catch (NoSuchAlgorithmException e) {
        e.printStackTrace();
    } return hexString.toString();
}

Answer 1

在代码中使用：

.setTnxId("0nf7" + System.currentTimeMillis())

然后稍后：

String tnxId="0nf7" + System.currentTimeMillis();

很可能不是唯一的问题，但是您真的想对这些使用两个不同的值吗（两次调用之间时间可能会改变）？在这两种情况下，您不希望使用相同的tnxid吗？

import java.util.Locale;

public class TransactionIdProvider {

    private final static String DEFAULT_PREFIX = "ID";

    // Convenient prime number for incrementing the counter
    private final static long ID_ADD = 0xF0AD;  // "f*ck off and die"

    // 64b counter with non-trivial start value
    private static long idCounter = 0x0101F00DDEADBEEFL;

    /**
     * Returns ID consisting of prefix string and 64b counter interleaved
     * with 32b per-4s-timestamp.
     * 
     * May produce identical ID (collision) when:
     * 1) class is reloaded within 4s
     *    (to fix: serialize "idCounter" upon shutdown/restart of VM, or
     *    modify prefix per start of VM)
     * 2) more than 2^64 IDs are requested within 4s (no fix, unexpected)
     * 3) more than 2^64 IDs are requested after cca. 550 years.
     *    (no fix, unexpected)
     * 4) more than one static instance of TransactionIdProvider is used
     *    (two or more VMs running the app) (to fix put different prefix in
     *    every VM/server running this)
     * 
     * Length of returned ID is prefix.length() + 24 alphanumeric symbols.
     */
    public static synchronized String getNewId(final String prefix) {
        idCounter += ID_ADD;    // increment counter
        // get 32b timestamp per ~4s (millis/4096) (good for ~550 years)
        final int timeStamp = (int)(System.currentTimeMillis()>>12);
        final int idPart1 = (int)(idCounter>>32);
        final int idPart2 = (int)(idCounter);
        return String.format(Locale.US, "%s%08X%08X%08X",
                             prefix, idPart1, timeStamp, idPart2);
    }

    public static String getNewId() {
        return getNewId(DEFAULT_PREFIX);
    }

}

不确定这个有多大的可用性，如果ID可能这么长。您可以随意使用/修改它。

我也在想，是不是我没有忘记一些重要的事情，却什么也想不起来了。

这一个的安全性方面仍然相当薄弱，因为在4S时间跨度内ID将像简单的相加，但至少它不会产生1、2、3...系列。