在AsyncTask中通过REST进行简单的HTTP登录

Question

我不熟悉编程和Android，这是我第一次尝试编程一个应用程序，但我已经无法登录了。登录必须与服务器连接，在get请求的帮助下，我将获得json数据，我可以使用它来验证登录数据（用户名）。允许使用该应用程序的人员已在数据库中。这应该很简单。在这个论坛中，我只能找到使用HTTPClient等的解决方案，但仅使用HTTPURLConnection已不再有效。我使用了LoginActivity模板

这是我的代码（我也没有使用JSON数据的经验）。这是我们的JSON数据结构：

{
  "id": "1234",
  "firstName": "xx",
  "lastName": "xy",
  "fullName": "xx xy"
}

public class UserLoginTask extends AsyncTask<String, Void, Boolean> {

    private final String mEmail;
    private final String mPassword;

    UserLoginTask(String email, String password) {
        mEmail = email;
        mPassword = password;
    }

    @Override
    protected Boolean doInBackground(String... params) {

       final String REQUEST_METHOD = "GET";
       final int READ_TIMEOUT = 15000;
       final int CONNECTION_TIMEOUT = 15000;
        // attempt authentication against a network service.
        //InputStream is;


        URL url = null;
        try {
            String username = params[0];
            String password = params[1];
            String inputLine;
            String result;

            url = new URL("URL//");
            //Connection with database
            urlConnection=(HttpURLConnection) url.openConnection();
            //Connect with database
            //urlConnection.connect();
            //Open stream;
            //is=urlConnection.getInputStream();

            //Set methods and timeouts
            urlConnection.setRequestMethod(REQUEST_METHOD);
            urlConnection.setReadTimeout(READ_TIMEOUT);
            urlConnection.setConnectTimeout(CONNECTION_TIMEOUT);

            //Connect to our URL
            urlConnection.connect();

            //TODO
            urlConnection.setRequestMethod("GET");
            urlConnection.setDoInput(true);

            //Create a new InputStreamReader
            InputStreamReader streamReader = new
                    InputStreamReader(urlConnection.getInputStream());
            //Create a new buffered reader and String Builder
            BufferedReader reader = new BufferedReader(streamReader);
            StringBuilder stringBuilder = new StringBuilder();

            //Check if the line we are reading is not null
            while((inputLine = reader.readLine()) != null){
                stringBuilder.append(inputLine);
            }

            //Close our InputStream and Buffered reader
            reader.close();
            streamReader.close();

            //Set our result equal to our stringBuilder
            result = stringBuilder.toString();

            //Proceed in function of status code response
            int status = urlConnection.getResponseCode();

        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    return false;

        /*for (String credential : DUMMY_CREDENTIALS) {
            String[] pieces = credential.split(":");
            if (pieces[0].equals(mEmail)) {
                // Account exists, return true if the password matches.
                return pieces[1].equals(mPassword);
            }
        }

        // TODO: register the new account here.
        return true;*/
    }

    @Override
    protected void onPostExecute(final Boolean success) {
        mAuthTask = null;
        showProgress(false);

        if (success) {
            finish();
        } else {
            mPasswordView.setError(getString(R.string.error_incorrect_password));
            mPasswordView.requestFocus();
        }
    }

我在Http服务类中也有这个：我的类httpservice中有这些方法：我如何使用这个？

private HttpURLConnection setup connection(String URL，Credentials credentials)抛出io exception { URL reqUrl = new URL(URL)；HttpURLConnection URL connection =(HttpURLConnection)requrl . open connection()；

    if (credentials != null && !credentials.getPassword().isEmpty() && !credentials.getUsername().isEmpty()) {
        urlConnection.setRequestProperty("Authorization", createBasicAuthString(credentials.getUsername(), credentials.getPassword()));
    }
    return urlConnection;
}


/**
 * Creates the String for the Authorization Header
 *
 * @param user
 * @param password
 * @return
 */
private String createBasicAuthString(String user, String password) {
    String notEncoded = user + ":" + password;
    String encodedAuth = Base64.encodeToString(notEncoded.getBytes(), Base64.DEFAULT);
    return "Basic " + encodedAuth;
}

Answer 1

像这样解析您的JSON数据，

 JSONObject jsonObject = new JSONObject(Your_Sring_data);
 String  id= jsonObject.getJsonString("id");
 String firstName= jsonObject.getJsonString("firstName");
 String lastName= jsonObject.getJsonString("lastName");
 String fullName= jsonObject.getJsonString("fullName");

并返回响应字符串，而不是doInBackground（）方法中的布尔成功变量，并通过上述代码解析该字符串