向TableLayout添加多行

Question

pupils=db.getAllPupilsPupil();
events=db.getAllEvents();
TableLayout tableLayout =(TableLayout) findViewById(R.id.table);
bubbleSort(events);
TableRow row= new TableRow(this);
TableRow.LayoutParams lp = new TableRow.LayoutParams(TableRow.LayoutParams.WRAP_CONTENT);
row.setLayoutParams(lp);
TextView tv;
tv = new TextView(this);
tv.setText("events ");
row.addView(tv);
for(int i=0;i<pupils.size();i++) {
    tv = new TextView(this);
    String name=pupils.get(i).getName()+" ";
    tv.setText(name);
    tv.setTextColor(getResources().getColor(R.color.colorBlack));
    row.addView(tv);
}
tableLayout.addView(row,0);
tableLayout.addView(row,1);

Answer 1

为了防止该错误消息：

指定的子级已有父级。

需要有两个TableRow实例（“指定的子级”），无论它们的内容是否重复：

for(int i=0; i < pupils.size(); i++) {

    TableRow row1 = new TableRow(this);
    TableRow row2 = new TableRow(this);
    TextView tv   = new TextView(this);

    tv.setText(pupils.get(i).getName());
    tv.setTextColor(getResources().getColor(R.color.colorBlack));

    row1.addView(tv);
    row2.addView(tv);

    tableLayout.addView(row1);
    tableLayout.addView(row2);
}