试图绕过错误：“main”java.util.InputMisMatchException

Question

输入整数:99
输入double:3.77
输入字符:z
输入字符串:Howdy
99 3.77z Howdy

public class BasicInput {

    public static void main(String[] args) {
        Scanner scnr = new Scanner(System.in);
        int userInt = 99;
        double userDouble = 3.77;
        char userChar='z';
        String userString="Howdy";


        System.out.println("Enter integer: ");
        userInt = scnr.nextInt();

        System.out.print("Enter double : ");
        userDouble = scnr.nextDouble();

        System.out.print("Enter Character, ");
        userChar = scnr.next().charAt(0);

        System.out.print("Enter String, ");
        userString = scnr.next();

        System.out.println(userInt+" "+userDouble+" "+userChar+" "+userString);

        System.out.println(userString+" "+userChar+" "+userDouble+" "+userInt);

        int castInt = (int) userDouble;

        System.out.println(""+userDouble+" cast to an integer is "+castInt);

        return;

    }
}

在java.util.scanner.throwfor（scanner.java:864)，java.util.scanner.next（scanner.java:1485)，java.util.scanner.nextint（scanner.java:2117)，java.util.scanner.nextint（scanner.java:2076)，basicinput.main（basicinput.java:13)

Answer 1

请阅读有关收到的异常的更多信息：https://docs.oracle.com/javase/7/docs/api/java/util/inputMismatchException.html

由扫描器引发，以指示检索到的标记与预期类型的模式不匹配，或者标记超出了预期类型的范围。