C程序称为"回文整数"二func。函数1//返回反转整数。函数2//如果回文返回true

Question

请帮帮忙

我正在用VisualBasic2010用C写一个程序，这个程序叫做“回文整数”。我需要写两个函数，一个是//返回整数的倒数。例如，reverse（456）返回654//并带有标题：--

倒整数（整数）

我需要写另一个函数，//返回true，如果数字是一个回文//标题：-

bool isPalindrome（整数）

我需要使用reverse函数来实现isAlindrome函数。如果一个数字与它本身相同，那么它就是一个回文。我的程序应该报告这个数字是否是回文。所有内容都在一个文件中。

我认为这个程序在我第一次编写代码时是有效的，不是作为两个函数，而是直接写入int main（）。但是我必须将代码放入指定的两个函数中，一旦我这样做并进行调整，我就会收到以下错误消息，黑色的cout显示框没有出现。下面是错误报告的片段，后面是完整的错误报告

：错误LNK2005：“int _cdecl反向（int）”（？反向@@YAHH@Z)已在驱动程序中定义。obj

：致命错误LNK1169:找到一个或多个乘法定义符号

我收到以下错误报告

1>------ Build started: Project: Palindrome integer, Configuration: Debug Win32 ------
1>Build started 12/7/2013 4:54:25 PM.
1>InitializeBuildStatus:
1>  Touching "Debug\Palindrome integer.unsuccessfulbuild".
1>ClCompile:
1>  All outputs are up-to-date.
1>ManifestResourceCompile:
1>  All outputs are up-to-date.
1>implementation.obj : error LNK2005: "int __cdecl reverse(int)" (?reverse@@YAHH@Z) already defined in Driver.obj
1>c:\documents and settings\dell\my documents\visual studio 2010\Projects\Palindrome integer\Debug\Palindrome integer.exe : fatal error LNK1169: one or more multiply defined symbols found
1>
1>Build FAILED.
1>
1>Time Elapsed 00:00:02.25
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

//Bellow是我的代码

#include <iostream>
#include <cmath>
#include <iomanip>

using namespace std;

//Retun reversal of an integer
int reverse(int number);              //function prototype

//Return true if number is a palindrome
bool isPalindrome(int number);            //function prototype


//Driver
int main()
{
    int usersNumber = 456; //0;    //a few lines commented tempararily for easier number testing
//  cout<<"Enter a number and I'll tell you if it's a Palindrome: ";
//  cin>> usersNumber;

bool palindromeToF = (isPalindrome(usersNumber));

    if (palindromeToF == true)
    {
        cout <<"YES the number is a Palindrome";
    }
    else
    {
        cout <<"NO the number is not a Palindrome";
    }


    return 0;
}

//function Implementation
//Retun reversal of an integer
int reverse(int number)
{
    //do while loop to count number of digits in Number
    int digitsCount = 0;
    double exponent1 = 1.0;
    int quotient;

    do
    {
        int tenToPower = pow( 10.0, exponent1);
    //  cout <<"tenToPower  "<< tenToPower <<"\t  ";
        quotient = (number / tenToPower);
    //      cout <<"exponent1  "<< exponent1<<"\t  ";
            exponent1++;

            //cout <<"quotient  "<< quotient<< "\t  "<<endl;
        digitsCount++;
    }while (!quotient == 0);


    //populating array "arrDigits" with integer's digits
    int *arrDigits = NULL;
    arrDigits = new int[digitsCount];
    double exponent2 = 0.0;
        for(int i = 0; i < digitsCount; i++)
        {
        int powerOfTen = pow( 10.0, exponent2);
    //cout <<endl<<"adding "<<((number / powerOfTen) % 10) <<" to sum";
        //cout <<powerOfTen;
        arrDigits[i]= ((number / powerOfTen) % 10);
        exponent2++;
        }

        //reverse number & populate array "arrDigRevers" with reversed order number 
        int *arrDigRevers = NULL;
        arrDigRevers = new int[digitsCount];
        int j = 0;
        int reversedNum = 0;
        double exponent3 = 0.0;
        for(int i = digitsCount-1; i >= 0; i--)
        {
            int powerOfTenB = pow( 10.0, exponent3);
        reversedNum += (powerOfTenB * arrDigits[i]);    //return of reverse func.
        exponent3++;

        /*   //reversed integer put into array 
        if(j < digitsCount)
        {
            arrDigRevers[j] = arrDigits[i];
            //cout <<"\t"<< "arrDigRevers"<<"["<< j<<"]="<< arrDigRevers[j]<<" "<< "arrDigits"<<"["<< j<<"]="<< " "<<arrDigits[j]<<" ";
            j++;
        }
        */

        }

        delete[] arrDigits;
        delete[] arrDigRevers;
        arrDigits = NULL;
        arrDigRevers = NULL;

        //cout <<endl<<"reversed number is "<< reversedNum;

        return reversedNum;
}


//function Implementation 
//Return true if number is a palindrome
bool isPalindrome(int number)
{
    if(number == reverse(number))
        {
            return true;
        }
        else
        {
            return false;
        }
}

Answer 1

答案就在这里：

<代码>1

似乎在两种实现中都定义了int reverse（int number）。cpp和司机。cpp。您需要从项目中重命名或删除其中一个定义。