如何从InputStream中获取Java文件的绝对路径？

Question

InputStream istream = this.getClass().getClassLoader().getResourceAsStream("config.xml");
if(istream != null) {
    System.out.println("Found config.xml!");

    StringBuffer fileData = new StringBuffer(1000);
    BufferedReader reader;
    try {
        reader = new BufferedReader(new FileReader(fileName));
        char[] buf = new char[1024];
        int numRead = 0;
        while((numRead=reader.read(buf)) != -1) {
            String readData = String.valueOf(buf, 0, numRead);
            fileData.append(readData);
            buf = new char[1024];
            reader.close();
        }
    } catch (FileNotFoundException fnfExc) {
        throw new RuntimeException("FileNotFoundException: " + fnfExc.getMessage());
    } catch (IOException ioExc) {
        throw new RuntimeException("IOException: " + ioExc.getMessage());
    }
}

Found config.xml!
Exception in thread "main" java.lang.RuntimeException: FileNotFoundException: config.xml (No such file or directory)
    at com.me.myapp.Configurator.readConfigFileFromClasspath(Configurator.java:556)
    at com.me.myapp.Configurator.<init>(Configurator.java:34)
    ...rest of stack trace omitted for brevity

Answer 1

您使用来自类加载程序的资源。

而不是做：

InputStream istream = this.getClass().getClassLoader().getResourceAsStream("config.xml");

做：

URL url = getClass().getResource("config.xml");