从PHP中的绝对路径获取相对路径

Question

键入标题时，我注意到有关此问题的一些类似问题，但它们似乎不在PHP中。那么用PHP函数解决该问题的方法是什么？

待指定。

$a="/home/apache/a/a.php";
$b="/home/root/b/b.php";
$relpath = getRelativePath($a,$b); //needed function,should return '../../root/b/b.php'

有什么好主意吗？谢谢。

Answer 1

试试这个：

function getRelativePath($from, $to)
{
    // some compatibility fixes for Windows paths
    $from = is_dir($from) ? rtrim($from, '\/') . '/' : $from;
    $to   = is_dir($to)   ? rtrim($to, '\/') . '/'   : $to;
    $from = str_replace('\\', '/', $from);
    $to   = str_replace('\\', '/', $to);

    $from     = explode('/', $from);
    $to       = explode('/', $to);
    $relPath  = $to;

    foreach($from as $depth => $dir) {
        // find first non-matching dir
        if($dir === $to[$depth]) {
            // ignore this directory
            array_shift($relPath);
        } else {
            // get number of remaining dirs to $from
            $remaining = count($from) - $depth;
            if($remaining > 1) {
                // add traversals up to first matching dir
                $padLength = (count($relPath) + $remaining - 1) * -1;
                $relPath = array_pad($relPath, $padLength, '..');
                break;
            } else {
                $relPath[0] = './' . $relPath[0];
            }
        }
    }
    return implode('/', $relPath);
}

这将给

$a="/home/a.php";
$b="/home/root/b/b.php";
echo getRelativePath($a,$b), PHP_EOL;  // ./root/b/b.php

和

$a="/home/apache/a/a.php";
$b="/home/root/b/b.php";
echo getRelativePath($a,$b), PHP_EOL; // ../../root/b/b.php

和

$a="/home/root/a/a.php";
$b="/home/apache/htdocs/b/en/b.php";
echo getRelativePath($a,$b), PHP_EOL; // ../../apache/htdocs/b/en/b.php

和

$a="/home/apache/htdocs/b/en/b.php";
$b="/home/root/a/a.php";
echo getRelativePath($a,$b), PHP_EOL; // ../../../../root/a/a.php