在C++中选择选项2时不显示输出

Question

所以当我在选项1中输入我的输入后，我选择继续。我的输入信息在选择选项2时消失了。我刚开始我的编程课程，所以请给我很多建议。这是这里的输出输入图像描述

struct Human
{
    string name;
    string foods;
    string date;

};

char option;

int main()
{
    do
        {
            int user;
            cout << "You" <<endl;
            cout << "\nChoose one from the menu below" <<endl;
            cout << "1 Enter information" <<endl;
            cout << "2 See information stored" <<endl;
            cout << "\nEnter your option" <<endl;
            cin >> user;
           Human me;
            switch(user)
            {
            case 1:
                {
                    cin.ignore(100, '\n');
                    cout << "\nEnter your name: ";
                    getline(cin, me.name, '\n');
                    cout << "Enter your favorite foods: ";
                    getline(cin, me.foods, '\n');
                    cout << "Enter your birthday: ";
                    getline(cin, me.date, '\n');
                    break;
                }
            case 2:
                {
                    cin.ignore(100, '\n');
                    cout << "Your name is: " << me.name<<endl;
                    cout << "Your favorite foods are: " <<me.foods<<endl;
                    cout << "Your birthday is: " <<me.date<<endl;
                    break;
                }
            }
            cout << "\nDo you wish to continue?" <<endl;
            cout << "Enter 'y' to continue and 'n' to exit" <<endl;
            cout << "Your choice:";
            cin >> option;
        }while(option == 'y');

    return 0;
}

Answer 1

在do-while循环的每次迭代中都创建一个新的human me；。当您在一次迭代中读取ME的输入时，下一次迭代中的ME将不会知道这一点。

阅读“作用域”，将声明human me；移到循环之外可能会达到您所期望的效果。