Python计算两个json之间的差异百分比

Question

我有一些本地json文件。例如:

JSON 1

{
"events":{
  "id1":{
     "name":"Marcus",
     "surname":"Redwhite",
     "age":"22",
     "text":{
        "description":"Some description ...",
        "title":"title of description"
     }
   },
  "id2":{
     "name":"Fred",
     "surname":"Rose",
     "age":"30",
     "text":{
        "description":"Some description ...",
        "title":"title of description"
     }
   }
}

JSON 1修改

{
"events":{
  "id1":{
     "name":"Marcus Modified",
     "surname":"Redwhite Modified",
     "age":"22",
     "text":{
        "description":"Some description ...",
        "title":"title of description Modified"
     }
   },
  "id2":{
     "name":"Fred",
     "surname":"Rose Modified",
     "age":"50",
     "text":{
        "description":"Some description ... Modified",
        "title":"title of description"
     }
   }
}

我必须比较这些Json文件（在这个示例中，姓名字段、姓氏字段、年龄字段和文本字段被修改），我必须计算它们之间的差异百分比（绘制饼图或任何其他图形）。有办法做到这一点吗？

import json
import glob

# get list of All json files in different folders:
originalJsonFilesList = glob.glob("C:/Python/OriginalJson/*.json")
modifiedJsonFilesList = glob.glob("C:/Python/ModifiedJson/*.json")

# Loop all list
for originalfile, modifiedFile in originalJsonFilesList, modifiedJsonFilesList:
    
    # Opening JSON files (original and modified)
    originalJson = open(originalfile)
    modifiedJson = open(modifiedFile)
   
    # load as dictionary
    data1 = json.load(originalJson)
    data2 = json.load(modifiedJson)
  
    #############################################
    # Something for calculateing difference 
    # of percentage between data1 and data2
    ############################################
  
    # Closing files
    originalJson.close()
    modifiedJson.close()

Answer 1

第一：

将您的json转换为cript

dict_json1=json.loads（json_1）

dict _ JSON _ modified = JSON . loads(JSON _ modified)

第二：

将它们转换为设置：

dict_json1dict_json1.items

dict _ JSON _ modified = set(dict _ JSON _ modified . items())

diff = dict_json1 ^ dict_json_modified

打印（差异）

Answer 2

你需要实现一个叫做Levenshtein距离度量的算法

还有一个问题与你的情况相似，有一个替代解决方案，你可以看看。

您也可以从difflib中检查SequenceMatcher