jQuery-在PHP while循环中检查一个输入框和另一个输入框

Question

我在编程一个订单提交页面时遇到了一个相当大的问题，该页面的目的是提交一个订单的争议--提供两个字段被填写，但只有当一个字段少于另一个字段时。

基本上，一个是下拉，另一个是争端框，查询如下：

如果DispotestExtBox=“”而下拉框=“请选择...”

一切正常-提交按钮已启用

如果DisportestExtBox！=“”而下拉框=“请选择...”

错误（反之亦然，因此如果填充了Disponents但dropwn=请选择...）-“提交”按钮已禁用

如果DispotestExtox！=“”且下拉框=“其他”

一切正常-提交按钮已启用

如果DispotestExtBox>shippedbox

错误-“提交”按钮已禁用

<table>
                <thead>
                    <tr><th>Item ID</th><th>Description</th><th>Dispute Quantity</th><th>Shipped Quantity</th><th>Ordered Quantity</th><th>Reason</th></tr>
                </thead>
                <tbody>
                    <?php
                        $data = mysql_query("SELECT * FROM `artran09` WHERE `invno` = '$invoiceno'") or die(mysql_error());
                        echo "<center>";
                        $i = -1;        
                        echo "<form action=\"submitdispute.php?invno=".$invoiceno."&ordate=".$placed."\" method=\"POST\" onsubmit=\"return confirm('Are you sure you are ready to dispute your order?');\">";

                            while ($info = mysql_fetch_array($data)) {              
                                $i += 1;                                    
                                echo "<tr>"; 
                                echo "<td>".$info['item']."</td>"; 
                                echo "<td>".$info['descrip']."</td>";       

                                echo "<td><input type=\"text\" input name=".$i." onKeyPress=\"return numbersonly(this, event)\"  maxLength=\"3\"></td>"; 

                                echo "<td><input type=\"text\" value=".$info['qtyshp']." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\" disabled=\"disabled\"></td>"; 

                                echo "<td><input type=\"text\" value=".$info['qtyord']." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\" disabled=\"disabled\"></td>"; 

                                echo "<td><select name = \"reason$i\">";
                                echo "<option>Please Select...</option>";
                                echo "<option>Short/Not received</option>";
                                echo "<option>Damaged Goods</option>";
                                echo "<option>Product Not Ordered</option>";                    
                                echo "</select></td>";

                                echo "</tr>"; 
                            }

                    ?>
                </tbody>
            </table>
        </div>
    </div>
    <p><input type = "submit" value = "Dispute" name ="Submit">
    </form>

谢谢，希望大家能帮忙！

为Wolf/任何能提供帮助的人编辑-这里的代码是怎么回事：

--我编辑的代码--

function validateSubmit(){


   // this will loop through each row in table
   // Make sure to include jquery.js
   $('tr').each( function() {
      // Find first input
      var input1 = $(this).find('input').eq(0);
      var qty1 = input1.val();
      // Find Second input
      var input2 = $(this).find('input').eq(1);
      var qty2 = input2.val();
      // Find third input
      var input3 = $(this).find('input').eq(2);
      var qty3 = input3.val();
      // Find select box
      var selectBx = $(this).find('select');
      var selectVal = selectBx.val();
      // Add your validation code here for the inputs and select
      // Return true if all validations are correct
      // Else return false
        if(qty1 = "" && selectVal = "Please Select...") {
            return true;
            alert("You have an error somewhere, please check over your quantites.");
            break;
        }
        if (qty1 > qty2) {
            return false;
            alert("You have an error somewhere, please check over your quantites.");
            break;
        }
   });


}

Answer 1

        return true;
        alert("You have an error somewhere, please check over your quantites.");
        break;

如果调用return，当前函数的执行将立即停止，并返回值。这意味着return语句执行后没有任何内容。alert()将不运行，因为函数以returntrue结尾。