hamcrest：使用hamcrest在逻辑上比较自定义类的两个集合

Question

我有两个收藏

public class Dumb {
    private String id;

    //setters & getters
}

简明扼要地，

@Test
public void test() {
    Collection<Dumb> actual = new ArrayList<Dumb>();
    Dumb actualDumbOne = new Dumb();
    actualDumbOne.setId("1");
    Dumb actualDumbTwo = new Dumb();
    actualDumbTwo.setId("2");
    actual.add(actualDumbOne);
    actual.add(actualDumbTwo);

    Collection<Dumb> expected = new ArrayList<Dumb>();
    Dumb expectedDumbOne = new Dumb();
    expectedDumbOne.setId("1");
    Dumb expectedDumbTwo = new Dumb();
    expectedDumbTwo.setId("2");
    expected.add(expectedDumbOne);
    expected.add(expectedDumbTwo);

    assertThat(expected, containsInAnyOrder(actual));
}

它失败的原因是：

Expected: iterable over [<[Dumb@56114349, Dumb@46c28400]>] in any order
     but: Not matched: <Dumb@2d6abfc7>

重要提示：我无法更改Dumbcode，它是第三方类。重要提示：我需要比较Dumb。id等于Dumb。id。

有什么想法吗？




Answer 1

如果你只需要比较一下哑巴。id成员，您可以将id提取到列表中并比较生成的id列表。

    List<String> actualIds = actual.stream().map(Dumb::getId).collect(Collectors.toList());
    List<String> expectedIds = expected.stream().map(Dumb::getId).collect(Collectors.toList());

    assertThat(expectedIds, containsInAnyOrder(actualIds.toArray()));