Pig Latin翻译

Question

因此，我有一个基本的Pig Latin翻译器，只能翻译一个单词。

def Translate(Phrase):
Subscript = 0

while Phrase[Subscript] != "a" or Phrase[Subscript] != "e" or Phrase[Subscript] != "i" or           
  Phrase[Subscript] != "o" or Phrase[Subscript] != "u":

  Subscript += 1
if Phrase[Subscript] == "a" or Phrase[Subscript] == "e" or Phrase[Subscript] == "i" or

Phrase[Subscript] == "o" or Phrase[Subscript] == "u":  
return Phrase[Subscript:] + Phrase[:Subscript] + "ay"

有人可以协助我编辑此翻译器以使用多个单词吗？谢谢。

Answer 1

这是Pig Latin方言，考虑了单词的发音方式：

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import re

sentences = ["Pig qoph an egg.",
             "Quiet European rhythms.",
             "My nth happy hour.",
             "Herb unit -- a dynasty heir."]
for sent in sentences:
    entsay = " ".join(["".join(map(to_piglatin, re.split("(\W+)", nonws)))
                       for nonws in sent.split()])
    print(u'"{}" → "{}"'.format(sent, entsay))

输出量

“猪qoph一个鸡蛋。” →“ igpay ophqay anway鸡蛋路。”
“安静的欧洲节奏。” →“ ietquay uropeaneay ythmsrhay。”
“我的第n个欢乐时光。” →“ ymay nthway appyhay小时制。”
“草药单位-王朝继承人。” →“草帽itunay-离开ynastyday继承人”。

注意：

• "-way" 后缀用于以元音开头的单词
• qu 在“安静”中被视为一个单位
• European，unit从辅音开始
• y 在“节奏”中，“王朝”是元音
• nth，hour，herb，heir开始以元音

在哪里to_piglatin()：

from nltk.corpus import cmudict # $ pip install nltk
# $ python -c "import nltk; nltk.download('cmudict')"

def to_piglatin(word, pronunciations=cmudict.dict()):
    word = word.lower() #NOTE: ignore Unicode casefold
    i = 0
    # find out whether the word start with a vowel sound using
    # the pronunciations dictionary
    for syllables in pronunciations.get(word, []):
        for i, syl in enumerate(syllables):
            isvowel = syl[-1].isdigit()
            if isvowel:
                break
        else: # no vowels
            assert 0
        if i == 0: # starts with a vowel
            return word + "way"
        elif "y" in word: # allow 'y' as a vowel for known words
            return to_piglatin_naive(word, vowels="aeiouy", start=i)
        break # use only the first pronunciation
    return to_piglatin_naive(word, start=i)

def to_piglatin_naive(word, vowels="aeiou", start=0):
    word = word.lower()
    i = 0
    for i, c in enumerate(word[start:], start=start):
        if c in vowels:
            break
    else: # no vowel in the word
        i += 1
    return word[i:] + word[:i] + "w"*(i == 0) + "ay"*word.isalnum()

要将文本拆分为句子，可以使用nltk标记符来分隔单词。可以修改代码以尊重字母的大小写（大写/小写），紧缩。