在Python中从CSV文件读取行

Question

我有一个CSV文件，下面是其外观示例：

Year:  Dec: Jan:
1      50   60
2      25   50
3      30   30
4      40   20
5      10   10

我知道如何读取文件并打印每列（例如- ['Year', '1', '2', '3', etc]）。但是我真正想做的是读取行，就像这样['Year', 'Dec', 'Jan']，然后['1', '50', '60']依此类推。

然后，我想将这些数字存储['1', '50', '60']到变量中，以便稍后将它们总计（例如）：

Year_1 = ['50', '60']。那我可以做sum(Year_1) = 110。

我将如何在Python 3中做到这一点？

Answer 1

您可以执行以下操作：

with open("data1.txt") as f:
    lis = [line.split() for line in f]        # create a list of lists
    for i, x in enumerate(lis):              #print the list items 
        print "line{0} = {1}".format(i, x)

# output 
line0 = ['Year:', 'Dec:', 'Jan:']
line1 = ['1', '50', '60']
line2 = ['2', '25', '50']
line3 = ['3', '30', '30']
line4 = ['4', '40', '20']
line5 = ['5', '10', '10']

要么 ：

with open("data1.txt") as f:
    for i, line in enumerate(f):             
        print "line {0} = {1}".format(i, line.split())

# output         
line 0 = ['Year:', 'Dec:', 'Jan:']
line 1 = ['1', '50', '60']
line 2 = ['2', '25', '50']
line 3 = ['3', '30', '30']
line 4 = ['4', '40', '20']
line 5 = ['5', '10', '10']

编辑：

with open('data1.txt') as f:
    print "{0}".format(f.readline().split())
    for x in f:
        x = x.split()
        print "{0} = {1}".format(x[0],sum(map(int, x[1:])))

# output          
['Year:', 'Dec:', 'Jan:']
1 = 110
2 = 75
3 = 60
4 = 60
5 = 20