rectf的x坐标java_java-缩放和缩放后屏幕坐标和图像坐标之间的转换
我有一堂课,负责管理从屏幕坐标到图像坐标的转换.
但是,我有一个“一个错误”.
以下给出了318、198,而不是319、199：
@Test
public void test6rightScreenCornerToImageCoOrdAfterZoomingAndScaling() {
PointTranslation pointTranslation = new PointTranslation();
pointTranslation.setOriginalSize(0, 0, 320, 200); // original image
pointTranslation.zoomIn(9, 9, 310, 190); // zoomed image starting at 9,9
pointTranslation.scale(0, 0, 800, 800);
Point translatedPoint = pointTranslation.transformPoint(799,799);
System.out.println(testName.getMethodName() + " : " + translatedPoint.toString());
assertTrue(translatedPoint.x == 319);
assertTrue(translatedPoint.y == 199);
}
================================================= ===========
完整清单：
package gtx;
import org.eclipse.swt.graphics.Point;
import org.eclipse.swt.internal.gdip.PointF;
import org.eclipse.swt.internal.gdip.RectF;
@SuppressWarnings("restriction")
public class PointTranslation {
RectF originalSize = null;
RectF currentSize = null;
RectF scaledSize = null;
public void setOriginalSize(int originX, int originY, int width, int height) {
originalSize = getRectangle(originX, originY, width, height);
currentSize = originalSize;
}
public void zoomIn(int originX, int originY, int width, int height) {
// System.out.println("addTranslation: " + originX + " " + originY + " "
// + width + " " + height);
currentSize = getRectangle(originX, originY, width, height);
}
public void scale(int originX, int originY, int width, int height) {
// System.out.println("addTranslation: " + originX + " " + originY + " "
// + width + " " + height);
scaledSize = getRectangle(originX, originY, width, height);
}
public boolean isPointWithinBounds(Point point) {
return isPointWithinBounds(point.x, point.y);
}
public boolean isPointWithinBounds(int xPos, int yPos) {
boolean ret = false;
if (scaledSize != null) {
RectF sourceRec = scaledSize;
int xBounds = (int) (sourceRec.Width + sourceRec.X);
int yBounds = (int) (sourceRec.Height + sourceRec.Y);
ret = (xPos < xBounds) && (yPos < yBounds) && (xPos > sourceRec.X) && (yPos > sourceRec.Y);
}
return ret;
}
public Point transformPoint(Point point) {
return transformPoint(point.x, point.y);
}
public Point transformPoint(int xPos, int yPos) {
Point sourcePoint = new Point((int) xPos, (int) yPos);
Point retPoint = sourcePoint;
if (this.scaledSize != null) {
retPoint = transformPoint(this.scaledSize, this.currentSize, sourcePoint);
}
return retPoint;
}
/*
* Rectangle 1 has (x1, y1) origin and (w1, h1) for width and height, and
* Rectangle 2 has (x2, y2) origin and (w2, h2) for width and height, then
*
* Given point (x, y) in terms of Rectangle 1 co-ords, to convert it to
* Rectangle 2 co-ords: xNew = ((x-x1)/w1)*w2 + x2; yNew = ((y-y1)/h1)*h2 +
* y2;
*/
private Point transformPoint(RectF source, RectF destination, Point intPoint) {
PointF point = new PointF();
point.X = intPoint.x;
point.Y = intPoint.y;
return transformPoint(source, destination, point);
}
private Point transformPoint(RectF source, RectF destination, PointF point) {
return new Point((int) ((((point.X - source.X) / source.Width) * destination.Width + destination.X)),
(int) ((((point.Y - source.Y) / source.Height) * destination.Height + destination.Y)));
}
private RectF getRectangle(int x, int y, int width, int height) {
RectF rect = new RectF();
rect.X = x;
rect.Y = y;
rect.Height = height;
rect.Width = width;
return rect;
}
private PointF getPoint(int x, int y) {
PointF retPoint = new PointF();
retPoint.X = x;
retPoint.Y = y;
return retPoint;
}
public void reset() {
this.originalSize = null;
this.currentSize = null;
this.scaledSize = null;
}
}
更新：
我的问题肯定是四舍五入.奇怪的是,对于某些测试用例,我需要向上舍入以获得正确的点,有时我需要向上舍入.我缺少诸如缩放因子之类的东西.任何建议如何正确地在两个矩形之间进行平移？
更新2：
我尝试了以下方法,但仍然不满意：
private Point transformPoint(RectF source, RectF destination, PointF point) {
float xPercent = normalize(point.X,source.X,source.Width);
float destX = xPercent*(Math.abs(destination.Width - destination.X)) + destination.X;
float yPercent = normalize(point.Y,source.Y,source.Height);
float destY = yPercent*(Math.abs(destination.Height - destination.Y)) + destination.Y;
System.out.println("Float x,y: " + destX + ", " + destY);
System.out.println("Ceil Float x,y: " + Math.floor(destX) + ", " + Math.floor(destY) );
return new Point((int)Math.floor(destX), (int)Math.floor(destY));
}
private float normalize(float value, float min, float max) {
return Math.abs((value - min) / (max - min));
}
解决方法:
在运行测试用例并逐步执行代码时,我的调试显示了以下替代内容…
transformPoint(RectF source, RectF destination, PointF point) {
return new Point (
(int) (((( 799 - 0 ) / 800 ) * 310 ) + 9 )),
(int) (((( 799 - 0 ) / 800 ) * 190 ) + 9 ))
);
}
该方程式的前半部分返回318.6125.等式的后半部分返回198.7625.
你需要
>修改方程式,以便将int转换截断为
期望值(例如末尾为1)
>在转换为int之前四舍五入
>与结果共存
正如Mathew指出的那样,连续多次翻译使问题变形和放大,就像平均平均值一样.
标签：zooming,translation,scaling,java
来源： https://codeday.me/bug/20191118/2028145.html