java - 为什么虚拟线程无法在虚拟线程池中执行?

Question

环境: java21
问题: methods5不会输出log.info的内容, methods6正常打印log.info的内容

    private static void methods5() {        ThreadFactory tf = Thread.ofVirtual().factory();        try (ExecutorService executor = Executors.newVirtualThreadPerTaskExecutor()) {            Thread vt = tf.newThread(() -> log.info("vt task executed."));            for (int i = 0; i < 5; i++) {                executor.submit(vt).get();            }        } catch (ExecutionException | InterruptedException e) {            throw new RuntimeException(e);        }    }    private static void methods6() {        try (ExecutorService executor = Executors.newFixedThreadPool(5)) {            Thread thread = new Thread(() -> log.info("thread task executed."));            for (int i = 0; i < 5; i++) {                try {                    executor.submit(thread).get();                } catch (InterruptedException | ExecutionException e) {                    // 处理异常                }            }        }    }

Answer 1

正确的做法是给调度器传真正的线程对象，它会以虚拟线程形式运行，而不是给它传虚拟线程，要么你就干脆直接对虚拟线程使用start()方法
改法一：

private static void methods5() {  try (ExecutorService executor = Executors.newVirtualThreadPerTaskExecutor()) {      Thread vt = new Thread(() -> System.out.println("vt task executed."));      for (int i = 0; i < 5; i++) {          executor.submit(vt).get();      }  } catch (ExecutionException | InterruptedException e) {      throw new RuntimeException(e);  }  }

改法二：

private static void methods5() {  try (ExecutorService executor = Executors.newVirtualThreadPerTaskExecutor()) {      for (int i = 0; i < 5; i++) {          executor.submit(()->{              System.out.println("vt task executed.");          });      }  }}

另外虚拟线程没有必要使用池化技术，因为创建和销毁的代价非常小，池化的话属于是违背初心了