c++ - C怎么实现键盘输入后右对齐输出？

Question

while (form[n1++] = _getch())
    {
        if (form[n1 - 1] == '=')
            break;
        if (form[n1 - 1] == 'd' || form[n1 - 1] == 'D')
        {
            printf("\b \b\b \b");
            n1 -= 2;
            continue;
        }
        if (form[n1 - 1] == 'q' || form[n1 - 1] == 'Q')
            exit(0);
        printf("%c", form[n1 - 1]);
    }

以上是我的源码，想要代码实现不回车就读取键盘输入

Answer 1

#include <stdio.h>
#include <conio.h>

int main() {
    char ch;
    while ((ch = _getch()) != '\r') {  // '\r' 回车键的ASCII码
        printf("%*c\n", 80, ch);  // 80对齐的宽度
    }
    return 0;
}