问题：
如何在java中设置数组中JButtons的颜色？
单于钊
假设有一个名称按钮数组：
私有JButton按钮[]=新JButton[9]
如何将此数组中所有按钮的颜色设置为蓝色？
这是我的全部代码：这是一个使用按钮的井字游戏。
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.awt.BorderLayout;
public class TicTacToe implements ActionListener {
private JButton buttons[] = new JButton[9];
private JFrame window = new JFrame("Tic Tac Toe");
private boolean win = false;
private int count = 0;
private int Xwins = 0, Owins = 0;
private String letter = "";
private int[][] winCombinations = new int[][] {
{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, //horizontal wins
{0, 3, 6}, {1, 4, 7}, {2, 5, 8}, //vertical wins
{0, 4, 8}, {2, 4, 6} //diagonal wins
};
String name1 = JOptionPane.showInputDialog("Please enter first player's name");
String name2 = JOptionPane.showInputDialog("Please enter second player's name");
public TicTacToe(){
JOptionPane.showMessageDialog(null,"Remember Player 1 is X and Player 2 is O.");
window.setSize(300,300);
window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
window.setLayout(new GridLayout(3,3));
window.setVisible(true);
for(int i=0; i<=8; i++){
buttons[i] = new JButton();
window.add(buttons[i]);
buttons[i].addActionListener(this);
buttons[i].setBackground(Color.MAGENTA);
}
for (JButton button: buttons) {
button.setBackground(Color.BLUE);
}
}
public void actionPerformed(ActionEvent event) {
count++;
if(count % 2 == 0){
letter = "O";
}else{
letter = "X";
}
JButton pressedButton = (JButton)event.getSource();
pressedButton.setText(letter);
pressedButton.setEnabled(false);
pressedButton.setBackground(Color.WHITE);
//Determine who won
for(int i=0; i<=7; i++){
if( buttons[winCombinations[i][0]].getText().equals(buttons[winCombinations[i][1]].getText()) &&
buttons[winCombinations[i][1]].getText().equals(buttons[winCombinations[i][2]].getText()) &&
buttons[winCombinations[i][0]].getText() != ""){
win = true;
}
}
if(win == true){
if(letter == "X"){
JOptionPane.showMessageDialog(null, name1 + " wins the game!");
}else{
JOptionPane.showMessageDialog(null, name2 + " wins the game!");
}
playAgain();
}else if(count == 9 && win == false){
JOptionPane.showMessageDialog(null, "The game is tied!");
playAgain();
}
}
public void playAgain(){
if(letter == "X"){
Xwins++;
}else{
Owins++;
}
JOptionPane.showMessageDialog(null, name1 + " has won this many times: " + Xwins);
JOptionPane.showMessageDialog(null, name2 + " has won this many times: " + Owins);
int response = JOptionPane.showConfirmDialog(null, "Would you like to play again?", "Confirm", JOptionPane.YES_NO_OPTION, JOptionPane.QUESTION_MESSAGE);
if(response == JOptionPane.YES_OPTION){
reset();
}else{
System.exit(0);
}
}
public void reset() {
for(int i = 0; i<=8; i++) {
buttons[i].setText("");
buttons[i].setEnabled(true);
}
win = false;
count = 0;
}
public static void main(String[] args){
TicTacToe play = new TicTacToe();
}
}
共有3个答案
丌官晔
@808sound在正确的轨道上-一些标准的外观和感觉（例如Windows）使按钮的颜色变得奇怪/困难/难以更改。
在程序开始时，尝试通过设置LAF
UIManager.setLookAndFeel(UIManager.getCrossPlatformLookAndFeelClassName());
此处提供更多详细信息
樊宏义
您需要在重置方法的循环中将按钮颜色重置为蓝色：
buttons[i].setBackground(Color.blue);
下面是在我的机器和Mac OSX机器上生成的应用程序的外观。选择后，按钮变为白色：
public static void main(String[] args){
try {
// Set cross-platform Java L&F (also called "Metal")
UIManager.setLookAndFeel(UIManager.getCrossPlatformLookAndFeelClassName());
// alternatively, the following should load the default L&F for your system
//UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (Exception e) {}
TicTacToe play = new TicTacToe();
}
黄博艺
这实际上是JButton的副作用。
背景和内容是两个不同的概念。虽然您可以更改背景色，但它可能不会更改按钮的内容区域。事实上，在不同的外观和感觉下，它的行为可能会有所不同。
相反，使用JLabel，它更容易控制。。。
public class TicTacToe implements ActionListener {
private JLabel labels[] = new JLabel[9];
private JFrame window = new JFrame("Tic Tac Toe");
private boolean win = false;
private int count = 0;
private int Xwins = 0, Owins = 0;
private String letter = "";
private int[][] winCombinations = new int[][]{
{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, //horizontal wins
{0, 3, 6}, {1, 4, 7}, {2, 5, 8}, //vertical wins
{0, 4, 8}, {2, 4, 6} //diagonal wins
};
String name1 = JOptionPane.showInputDialog("Please enter first player's name");
String name2 = JOptionPane.showInputDialog("Please enter second player's name");
public TicTacToe() {
JOptionPane.showMessageDialog(null, "Remember Player 1 is X and Player 2 is O.");
window.setSize(300, 300);
window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
window.setLayout(new GridLayout(3, 3));
window.setVisible(true);
MouseHandler handler = new MouseHandler();
for (int i = 0; i <= 8; i++) {
labels[i] = new JLabel();
labels[i].setOpaque(true);
labels[i].setBorder(new LineBorder(Color.LIGHT_GRAY));
labels[i].setHorizontalAlignment(JLabel.CENTER);
window.add(labels[i]);
labels[i].addMouseListener(handler);
labels[i].setBackground(Color.MAGENTA);
}
// for (JButton button : buttons) {
// button.setBackground(Color.BLUE);
// }
}
public void actionPerformed(ActionEvent event) {
}
public void playAgain() {
if (letter == "X") {
Xwins++;
} else {
Owins++;
}
JOptionPane.showMessageDialog(null, name1 + " has won this many times: " + Xwins);
JOptionPane.showMessageDialog(null, name2 + " has won this many times: " + Owins);
int response = JOptionPane.showConfirmDialog(null, "Would you like to play again?", "Confirm", JOptionPane.YES_NO_OPTION, JOptionPane.QUESTION_MESSAGE);
if (response == JOptionPane.YES_OPTION) {
reset();
} else {
System.exit(0);
}
}
public void reset() {
for (int i = 0; i <= 8; i++) {
labels[i].setText("");
labels[i].setEnabled(true);
}
win = false;
count = 0;
}
public class MouseHandler extends MouseAdapter {
@Override
public void mouseClicked(MouseEvent event) {
count++;
if (count % 2 == 0) {
letter = "O";
} else {
letter = "X";
}
JLabel pressedLabel = (JLabel) event.getSource();
pressedLabel.setText(letter);
pressedLabel.setEnabled(false);
pressedLabel.setBackground(Color.WHITE);
//Determine who won
for (int i = 0; i <= 7; i++) {
if (labels[winCombinations[i][0]].getText().equals(labels[winCombinations[i][1]].getText())
&& labels[winCombinations[i][1]].getText().equals(labels[winCombinations[i][2]].getText())
&& labels[winCombinations[i][0]].getText() != "") {
win = true;
}
}
if (win == true) {
if (letter == "X") {
JOptionPane.showMessageDialog(null, name1 + " wins the game!");
} else {
JOptionPane.showMessageDialog(null, name2 + " wins the game!");
}
playAgain();
} else if (count == 9 && win == false) {
JOptionPane.showMessageDialog(null, "The game is tied!");
playAgain();
}
}
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (Exception ex) {
}
TicTacToe play = new TicTacToe();
}
});
}
}
您唯一的其他选择可能是创建一个只能够绘制背景色的按钮实现，这需要您从抽象按钮扩展，但老实说，这需要大量的工作。。。
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