Python 3 urllib产生TypeError：POST数据应该是字节或可迭代的字节。它不可能是类型str

Question

我试图将工作的Python 2.7代码转换成Python 3代码，我从urllib请求模块收到一个类型错误。

我使用内置的2to3 Python工具来转换下面的工作urllib和urllib2 Python 2.7代码：

import urllib2
import urllib

url = "https://www.customdomain.com"
d = dict(parameter1="value1", parameter2="value2")

req = urllib2.Request(url, data=urllib.urlencode(d))
f = urllib2.urlopen(req)
resp = f.read()

2to3模块的输出是以下Python 3代码：

import urllib.request, urllib.error, urllib.parse

url = "https://www.customdomain.com"
d = dict(parameter1="value1", parameter2="value2")

req = urllib.request.Request(url, data=urllib.parse.urlencode(d))
f = urllib.request.urlopen(req)
resp = f.read()

当运行Python 3代码时，会产生以下错误：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-56-206954140899> in <module>()
      5 
      6 req = urllib.request.Request(url, data=urllib.parse.urlencode(d))
----> 7 f = urllib.request.urlopen(req)
      8 resp = f.read()

C:\Users\Admin\Anaconda3\lib\urllib\request.py in urlopen(url, data, timeout, cafile, capath, cadefault, context)
    159     else:
    160         opener = _opener
--> 161     return opener.open(url, data, timeout)
    162 
    163 def install_opener(opener):

C:\Users\Admin\Anaconda3\lib\urllib\request.py in open(self, fullurl, data, timeout)
    459         for processor in self.process_request.get(protocol, []):
    460             meth = getattr(processor, meth_name)
--> 461             req = meth(req)
    462 
    463         response = self._open(req, data)

C:\Users\Admin\Anaconda3\lib\urllib\request.py in do_request_(self, request)
   1110                 msg = "POST data should be bytes or an iterable of bytes. " \
   1111                       "It cannot be of type str."
-> 1112                 raise TypeError(msg)
   1113             if not request.has_header('Content-type'):
   1114                 request.add_unredirected_header(

TypeError: POST data should be bytes or an iterable of bytes. It cannot be of type str.

我还读了另外两张票（ticket1和ticket2），其中提到了日期编码。

当我更改行f=urllib时。要求urlopen（req）到f=urllib。要求urlopen（请求编码（'utf-8'））我收到以下错误：AttributeError:'Request'对象没有属性'encode'

我一直在思考如何使Python 3代码正常工作。你能帮帮我吗？

Answer 1

我将python请求模块与ZOHO CRM API V2一起使用。它没有任何问题。下面是GET请求的示例工作代码：

import json
import requests

# API methods - https://www.zoho.com/crm/developer/docs/api/api-methods.html
# getrecords API Call
module_name = 'Deals'
authtoken = '*****'
api_url = "https://crm.zoho.com/crm/private/json/"+module_name+"/getRecords?authtoken="+authtoken+"&scope=crmapi&fromIndex=1&toIndex=2"

# GET Request
request_response = requests.get(
    url=api_url
    )
print(json.dumps(json.loads(request_response.text), sort_keys=True, indent=4, separators=(",", ": ")))
json_response = json.loads(request_response.text)

Answer 2

试试这个：

url = 'https://www.customdomain.com'
d = dict(parameter1="value1", parameter2="value2")

f = urllib.parse.urlencode(d)
f = f.encode('utf-8')

req = urllib.request.Request(url, f)

你的问题在于你处理字典的方式。

Answer 3

从文档中可以看出，urlencode的参数输出在作为数据发送到urlopen之前被编码为字节：

data = urllib.parse.urlencode(d).encode("utf-8")
req = urllib.request.Request(url)
with urllib.request.urlopen(req,data=data) as f:
    resp = f.read()
    print(resp)