如何删除js[duplicate]中数组的最后一个元素

Question

我有一个二维数组，其中最后的元素是空的。这样地：

data = [["1","2","3","","",""],["4","5","6","x","f",""],["7","8","9","",""]]

现在我想删除空元素，并获得正确的新大小。长度

我试着这样做，但不起作用：

        for (i = 0; i != data[2].length-1; i++) {
            if (data[2][i].isEmpty()) {
                data[2] = data[2].splice(i, 1);
            }
        }

有什么好办法吗？

Answer 1

使用。映射和。过滤器：

const data = [
  ['1', '2', '3', '', '', ''],
  ['4', '5', '6', 'x', 'f', ''],
  ['7', '8', '9', '', ''],
];

const cleanData = data.map(arr => arr.filter(value => value || false));

console.log(cleanData);

Answer 2

由于更改了数组的长度，因此在for（）循环中进行拼接非常棘手

使用map（）和filter（）

let data = [["1","2","3","","",""],["4","5","6","x","f",""],["7","8","9","",""]]

data = data.map(arr => arr.filter(e => e.trim()));  

console.log(JSON.stringify(data))

Answer 3

您可以使用Boolean作为保留truthy元素的回调进行过滤后映射数组。

var data = [["1", "2", "3", "", "", ""], ["4", "5", "6", "x", "f", ""], ["7", "8", "9", "", ""]];

data = data.map(a => a.filter(Boolean));

console.log(data);