阵列。使用Lambda排序，然后比较

Question

我是Java新手，我正在尝试使用Lambda表达式和比较器。我有一个具有其他getter和toString方法的公共类人员：

public class Person { 
    private String name;
    private int age;
    private int computers;
    private double salary;

public Person(String name, int age, int computers, double salary){
    this.name = name;
    this.age = age;
    this.computers = computers;
    this.salary = salary;
    }

public String getName(){
    return this.name;
}

public int getAge(){
    return this.age;
}

public int getComputers(){
    return this.computers;
}

public double getSalary(){
    return this.salary;
}
@Override
public String toString(){
    return "Name: " + getName() + ", age: "+ getAge() +
            ", N° pc: " + getComputers() + ", salary: " + getSalary();
}


}

现在我想对一个Person[]列表进行排序，首先按String（降序）进行比较，然后按年龄（升序）进行比较，然后按计算机数量（降序）进行比较，最后按Salary（升序）进行比较。我无法实现可比较，因为如果我重写compareTo方法，它应该是升序或降序，我需要两者。我想知道是否可以在不创建自己的比较器类的情况下做到这一点。基本上我的代码几乎是正确的，但我不知道如何逆转thenCompingInt（Person::getComputer）...

import java.util.Arrays;
import java.util.Comparator;


public class PersonMain {
   public static void main (String args[]){

    Person[] people = new Person[]{
            new Person("Adam",  30, 6, 1800),
            new Person("Adam",  30, 6, 1500),
            new Person("Erik",  25, 1, 1300),
            new Person("Erik",  25, 3, 2000),
            new Person("Flora", 18, 1, 800 ),
            new Person("Flora", 43, 2, 789),
            new Person("Flora", 24, 5, 1100),
            new Person("Mark",  58, 2, 2400)
    };

    Arrays.sort(people, Comparator.comparing(Person::getName).reversed()
            .thenComparingInt(Person::getAge)
            .thenComparingInt(Person::getComputers)
            .thenComparingDouble(Person::getSalary)
            );

    for (Person p: people)
        System.out.println(p);
  }
}

正确的输出应该是：

Name: Mark,  age: 58, N° pc: 2, salary: 2400.0
Name: Flora, age: 18, N° pc: 1, salary:  800.0
Name: Flora, age: 24, N° pc: 5, salary: 1100.0
Name: Flora, age: 43, N° pc: 2, salary:  789.0
Name: Erik,  age: 25, N° pc: 3, salary: 2000.0
Name: Erik,  age: 25, N° pc: 1, salary: 1300.0
Name: Adam,  age: 30, N° pc: 6, salary: 1500.0
Name: Adam,  age: 30, N° pc: 6, salary: 1800.0

提前感谢大家！

Answer 1

我认为您只需要单独创建计算机比较器：

Comparator.comparing(Person::getName).reversed()
          .thenComparingInt(Person::getAge)
          .thenComparing(Comparator.comparingInt(Person::getComputers).reversed())
          .thenComparingDouble(Person::getSalary)