从数组[复制]获取适当的对象

Question

我创建了一个如下数组：

arrayObject = [{one: "1", two: "2", three: "3", four: "4", five: "5"}, 
               {one: "1", two: "2", three: "3", four: "4", five: "5"}];

如何获取/过滤该数组，使其仅具有“1”、“2”和“5”元素，如下所示：

arrayObject = [{one: "1", two: "2", five: "5"}, 
               {one: "1", two: "2",  five: "5"}];

最好的方法是什么？

Answer 1

你可以像下面这样映射和使用传播

js lang-js prettyprint-override">arrayObject = [{one: "1", two: "2", three: "3", four: "4", five: "5"}, 
               {one: "1", two: "2", three: "3", four: "4", five: "5"}];
               
let filtered=arrayObject.map(a=>{

  const {three,four,...rest}=a;
  return rest;
});
console.log(filtered);

Answer 2

function extractObjectWithKeys(objects, keys) {
  return objects.reduce((acc, elem) => {
    let newObj = {};
    let filteredKeys = Object.keys(elem).filter(k => keys.includes(k));
    filteredKeys.forEach(key => {
      newObj[key] = elem[key];
    });
    return acc.concat(newObj);
  }, []);
}

const arrayObject = [
  {one: "1", two: "2", three: "3", four: "4", five: "5"}, 
  {one: "1", two: "2", three: "3", four: "4", five: "5"}
];

//Usage:
extractObjectWithKeys(arrayObject, ["one", "two", "five"])

Answer 3

你可以只映射想要的属性，然后从变量中解构一个新对象。

var array = [{ one: "1", two: "2", three: "3", four: "4", five: "5" }, { one: "1", two: "2", three: "3", four: "4", five: "5" }],
    result = array.map(({ one, two, five }) => ({ one, two, five }));

console.log(result);

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