mockito.mock在编写Junit测试时如何优于使用new？[关闭]

Question

我是第一次编写Junit测试，也是第一次使用Mockito框架。在用Java编写Junit测试时，使用mockito.mock()如何比使用new操作符更好地创建实例？

Answer 1

Mockito可用于注入当前测试上下文中可能不存在的依赖项，而不是创建用于测试的“虚拟”对象。这些模拟对象不是真实的，而是模拟类的“空”版本，您可以在这些模拟类上运行Mockito提供的各种行为模拟和结果验证方法。

例如，以下类：

class Thing {
    //Some external Dependency which provides the method 'int doWork()'
    private Dependency dependency;
    private int value;
    public void setDependency(Dependency dependency) {
        this.dependency = dependency;
    }
    public int getValue() {
        return value;
    }
    // Calculates something depending on the provided amount.
    public void calculate(int amount) {
        for(int i = 0; i < amount; i++) {
            value += dependency.doWork();
        }
    }
}

然后您可以在测试中执行以下操作：

@Test
public void should_calculate_five_times() {
    // Create mock object
    Dependency dependencyMock = Mockito.mock(Dependency.class);
    // Simulate the behaviour of the mock object
    Mockito.when(dependencyMock.doWork()).thenReturn(2);

    // Create object under test
    Thing thingToTest = new Thing();
    // Inject mock object
    thingToTest.setDependency(dependencyMock);
    // Execute method to test
    thingToTest.calculate(5);

    // Expected: dependency.doWork() should have been called 5 times
    Mockito.verify(dependencyMock, Mockito.times(5)).doWork();
    // Since dependencyMock returns 2, when doWork() is called, value should be 10
    Assert.assertEquals(10, thingToTest.getValue());
}