springdoc openapi规范生成继承With泛型

Question

我有一个Spring Boot（kotlin）项目，我使用springdoc openapi生成openapi 3规范。我的数据模型如下所示：

open class Animal
data class Cat(val catName: String) : Animal()
data class Dog(val dogName: String) : Animal()

open class Food<T : Animal>
class CatFood : Food<Cat>()
class DogFood : Food<Dog>()

还有一个简单的控制器，如下所示：

@GetMapping("/test")
fun test(): Food<out Animal> = DogFood()

生成的yaml为：

openapi: 3.0.1
info:
  title: OpenAPI definition
  version: v0
servers:
- url: http://localhost:8085
paths:
  /test:
    get:
      tags:
      - test-controller
      operationId: test
      responses:
        "200":
          description: default response
          content:
            '*/*':
              schema:
                $ref: '#/components/schemas/FoodAnimal'
components:
  schemas:
    FoodAnimal:
      type: object

这里的问题是我的控制器可以返回DogFood或CatFood，这在返回类型中指定。我期望生成的模式是：

openapi: 3.0.1
info:
  title: OpenAPI definition
  version: v0
servers:
- url: http://localhost:8085
paths:
  /test:
    get:
      tags:
      - test-controller
      operationId: test
      responses:
        "200":
          description: default response
          content:
            '*/*':
              schema:
                oneOf:
                  - $ref: '#/components/schemas/FoodAnimal'
                  - $ref: '#/components/schemas/DogFood'
                  - $ref: '#/components/schemas/CatFood'

components:
  schemas:
    FoodAnimal:
      type: object
    CatFood:
      allOf:
        - $ref: '#/components/schemas/FoodAnimal'
      type: object
    DogFood:
      allOf:
        - $ref: '#/components/schemas/FoodAnimal'
      type: object

有没有办法做到这一点？

Answer 1

我在使用OpenApi继承嵌套属性时遇到问题。

我使用JsonSubtype注释和泛型作为解决方法。

data class AnimalResponse<FoodResponse>(
    val id: UUID,
    val eats: FoodResponse
)

@JsonSubTypes(value = [
    JsonSubTypes.Type(
        value = CatFoodResponse::class,
        name = "CAT_FOOD"
    ), JsonSubTypes.Type(
        value = DogFoodResponse::class,
        name = "DOG_FOOD"
    )])
interface FoodResponse

这将显示动物响应模式中的所有类型的食物响应。

Answer 2

对于继承，只需在父类上添加@Schema注释：

@Schema(
        type = "object",
        title = "Food",
        subTypes = [CatFood::class, DogFood::class]
)
open class Food<T : Animal>
class CatFood : Food<Cat>()
class DogFood : Food<Dog>()

如果您需要使用oneOf的响应，则必须添加@响应：

@GetMapping("/test")
@ApiResponse(content = [Content(mediaType = "*/*", schema = Schema(oneOf = [Food::class, CatFood::class,DogFood::class]))])
fun test(): Food<out Animal> = DogFood()