在客户端捕获Rest异常

Question

我有一个从服务器端抛出的异常，我希望在客户端捕捉到这个异常。异常应该使用Jersey通过REST发送。这是我目前所掌握的：

定义我的异常：

public class MyException extends Exception implements Serializable {

    private static final long serialVersionUID = 1L;

    public MyException () {
        super();
    }
    public MyException (String msg)   {
        super(msg);
    }
    public MyException (String msg, Exception e)  {
        super(msg, e);
    }
}

@Provider
public class TestMapper implements ExceptionMapper<MyException> {

    @Override
    public Response toResponse(MyExceptionexception){
        return Response.status(Status.BAD_REQUEST).entity(exception.getMessage()).build(); 
    }
}

@PUT
@Path("calculate")
public void calculateMethod(String id) throws MyException{
   //Other code...
    throw new MyException("custom error message string");
    }       
}

public void calculateMethodClient(String id) throws MyException{
    client().put("/test/", "calculate", id);
}

public boolean testClient(){
    try {
        client.calculateMethodClient((String) id);
        return true;
    } catch (MyException) {
        return false;
    } catch (UniformInterfaceException e){
        return false;
    }
}

Answer 1

您需要检查客户端的状态代码，如果它是一个错误的请求，则在那里抛出异常以及从服务器获得的异常消息。