不一致js：如何确保机器人不会从列表中选择两个相同的单词

Question

所以我在discord.js做了一个猜谜游戏，机器人从列表中随机选择4个单词，把它们放在聊天中，你必须用同样的单词回复。以下是我试图做的一个缩写和简单的版本：

const profileModel = require("../models/profileSchema");
module.exports = {
    name: "guess",
    description: "guessing game",
    async execute(client, message, args, Discord, profileData) {
        let words = [
            "red",
             "orange",
             "yellow",
             "green",
             "blue",
             "purple",
             "pink",
             "black",
             "white"
         ]
         let firstWord = words[Math.floor(Math.random() * words.length)];
         let secondWord = words[Math.floor(Math.random() * words.length)];
         let thirdWord = words[Math.floor(Math.random() * words.length)]; 
         let fourthWord = words[Math.floor(Math.random() * words.length)];

         message.reply(`Type the following words into chat: \`${firstWord}\` \`${secondWord}\` \`${thirdWord}\` \`${fourthWord}\``)
           .then((msg) => {
               setTimeout(function() {
                   msg.edit('Type the words into chat!');
               }, 5000)});  
               message.channel.awaitMessages(m => m.author.id == message.author.id, { max: 1, time: 10000 }).then(collected => {
                   if (collected.first().content.toLowerCase() == `${firstWord} ${secondWord} ${thirdWord} ${fourthWord}`) {
                       message.reply('Correct!');
                   } else
                       message.reply('Incorrect');
               }).catch(() => {
                   message.reply('No answer after 10 seconds, time out.');
               });
           });
    }
}

我怎么才能让机器人不会两次选择同一个单词？例如，使它不能说“蓝色蓝色绿色橙色”之类的话。谢谢！

Answer 1

通过一种非常简单的方式，您可以执行以下操作：

1. 指定单词后，使用splice（）函数将元素从数组中剪断：

index = words.indexOf(firstWord);
words.splice(index, 1);

let firstWord = words[Math.floor(Math.random() * words.length)];
index = words.indexOf(firstWord);
words.splice(index, 1);
let secondWord = words[Math.floor(Math.random() * words.length)];
index = words.indexOf(secondWord);
words.splice(index, 1);
let thirdWord = words[Math.floor(Math.random() * words.length)];
index = words.indexOf(thirdWord);
words.splice(index, 1);
let fourthWord = words[Math.floor(Math.random() * words.length)];
index = words.indexOf(fourthWord);
words.splice(index, 1);

最后，bot将从words[]数组中删除该元素，直到调用该命令为止。

参考文献：

• splice（）函数