Netbeans平台与Jpa EclipsLink

Question

我在netbeans上创建了一个项目并添加了jpa，但是当我运行这个项目时，我接受了这个错误。我使用netbeans IDE。

package javaapplication11;

import java.io.Serializable;
import java.util.Objects;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

/**
 *
 * @author kB
 */
@Entity
@Table(name="room")
public class NewEntity implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "room_id")
    private int id;

    @Column(name = "room_name")
    private String name;

    public NewEntity() {
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Override
    public int hashCode() {
        int hash = 5;
        hash = 29 * hash + this.id;
        hash = 29 * hash + Objects.hashCode(this.name);
        return hash;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj) {
            return true;
        }
        if (obj == null) {
            return false;
        }
        if (getClass() != obj.getClass()) {
            return false;
        }
        final NewEntity other = (NewEntity) obj;
        if (this.id != other.id) {
            return false;
        }
        if (!Objects.equals(this.name, other.name)) {
            return false;
        }
        return true;
    }

    @Override
    public String toString() {
        return super.toString(); //To change body of generated methods, choose Tools | Templates.
    }





}

package javaapplication11;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;

/**
 *
 * @author kB
 */
public class JavaApplication11 {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        // TODO code application logic here

        EntityManagerFactory emf = Persistence.createEntityManagerFactory("JavaApplication11PU");
        EntityManager em = emf.createEntityManager();
        em.getTransaction().begin();
        NewEntity x = new NewEntity();
        x.setName("anan");
        em.persist(x);
        em.getTransaction().commit();
        em.close();
        emf.close();   
    }        
}

最后是我的persistence.xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
  <persistence-unit name="JavaApplication11PU" transaction-type="RESOURCE_LOCAL">
    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
    <class>javaapplication11.NewEntity</class>
    <properties>
      <property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/felek"/>
      <property name="javax.persistence.jdbc.user" value="root"/>
      <property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/>
      <property name="javax.persistence.jdbc.password" value=""/>
      <property name="javax.persistence.schema-generation.database.action" value="create"/>
    </properties>
  </persistence-unit>
</persistence>

Answer 1

这就是全部代码吗？

因为堆栈跟踪的末尾指向javaApplication11.java:29，这是main的符号，这很奇怪。