使用Actionbar选项卡在方向上显示错误的片段

Question

我已经实现了ActionBarsherlock的示例com.actionBarsherlock.sample.fragments，所有这些都工作得很好，直到当所选选项卡有子片段时设备方向发生变化。

一切都好：

一切都很好，可以旋转设备没有问题。现在，如果我在Fragment2中选择一个列表项来推入Fragment2Child1，在我旋转设备之前，一切都是好的。

设备旋转时不良：

tab1->Fragment1

int currentapiVersion = android.os.Build.VERSION.SDK_INT;
if (currentapiVersion >= android.os.Build.VERSION_CODES.ICE_CREAM_SANDWICH) {

            mTabManager.addTab(mTabHost.newTabSpec("new").setIndicator(getString(R.string.new_)), NewListSupportActivity.NewListFragment.class, null);
        mTabManager.addTab(mTabHost.newTabSpec("project").setIndicator(getString(R.string.project)), ProjectSupportActivity.ProjectListFragment.class, null);
        mTabManager.addTab(mTabHost.newTabSpec("setting").setIndicator(getString(R.string.settings)), SettingSupportActivity.SettingListFragment.class, null);

        if (savedInstanceState != null) {
            mTabHost.setCurrentTabByTag(savedInstanceState.getString("tab"));
        }

    } else {

public void addTab(TabHost.TabSpec tabSpec, Class<?> clss, Bundle args) {

    tabSpec.setContent(new DummyTabFactory(this.mActivity));
    final String tag = tabSpec.getTag();

    final TabInfo info = new TabInfo(tag, clss, args);

    // Check to see if we already have a fragment for this tab, probably
    // from a previously saved state. If so, deactivate it, because our
    // initial state is that a tab isn't shown.
    info.fragment = this.mActivity.getSupportFragmentManager().findFragmentByTag(tag);
    if (info.fragment != null && !info.fragment.isDetached()) {
        final FragmentTransaction ft = this.mActivity.getSupportFragmentManager().beginTransaction();
        ft.detach(info.fragment);
        ft.commit();
    }

    this.mTabs.put(tag, info);
    this.mTabHost.addTab(tabSpec);
}

@Override
public void onTabChanged(String tabId) {

    TabInfo newTab = mTabs.get(tabId);
    if (mLastTab != newTab) {
        FragmentTransaction ft = mActivity.getSupportFragmentManager().beginTransaction();
        if (mLastTab != null) {
            if (mLastTab.fragment != null) {
                ft.detach(mLastTab.fragment);
            }
        }
        if (newTab != null) {
            if (newTab.fragment == null) {
                newTab.fragment = Fragment.instantiate(mActivity, newTab.clss.getName(), newTab.args);
                ft.add(mContainerId, newTab.fragment, newTab.tag);
            } else {
                ft.attach(newTab.fragment);
            }
        }

        mLastTab = newTab;
        ft.commit();
        mActivity.getSupportFragmentManager().executePendingTransactions();
    }
}

以及推送Fragment2Child1或任何子级的代码

public void pushFragment(TradiesFragment current, TradiesFragment fragment) {

    fragment.setFragmentListener(this);
    final FragmentManager fm = this.fragment.getFragmentManager();
    final FragmentTransaction ft = fm.beginTransaction();
    ft.setCustomAnimations(R.anim.slide_in_right, R.anim.slide_out_left, android.R.anim.slide_in_left, android.R.anim.slide_out_right);
    ft.detach(current);
    ft.add(this.fragment.getId(), fragment);
    ft.addToBackStack(null);
    ft.commit();
}

Answer 1

这个问题没有答案。至少我能想到的没有一个不是彻头彻尾的丑陋。解决方案是将Fragment2Child1包装在一个活动中。当导航到fragment2child1activity时，最终会隐藏tab活动。并且用户每次都被迫导航回主活动（带有选项卡）。从好的方面来看，它实际上使UI更加简单。