如何从ElasticSearch响应中删除额外字段

Question

嗨，我是ElasticSearch的新手，我正在努力从ElasticSearch的响应中删除所有额外字段。请参见以下回复：

  "report": {
    "unique_users": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": 1234,
          "doc_count": 2,
          "user_details": {
            "hits": {
              "total": 2,
              "max_score": 1.4E-45,
              "hits": [
                {
                  "_index": "orders-test",
                  "_type": "order",
                  "_id": "2",
                  "_score": 0.0,
                  "_source": {
                    "customer_email": "[e-mail]",
                    "customer_phone": "476.824.4998 x498",
                    "customer_name": "Mohammed Abernathy"
                  }
                }
              ]
            }
          }
        },
        {
          "key": 5678,
          "doc_count": 1,
          "user_details": {
            "hits": {
              "total": 1,
              "max_score": 1.4E-45,
              "hits": [
                {
                  "_index": "orders-test",
                  "_type": "order",
                  "_id": "1",
                  "_score": 0.0,
                  "_source": {
                    "customer_email": "[e-mail]",
                    "customer_phone": "1-715-183-8343 x026",
                    "customer_name": "Richie Tillman II"
                  }
                }
              ]
            }
          }
        }
      ]
    }
  }

上面你可以看到响应中有一些附加字段，如_index、_type、_score、max_score等。我按照ElasticSearchresponse_filtering指南删除了这些字段，但对我不起作用。我还将filter_path参数传递给请求0.0.0.0:5000/v4/reports/user.json?filter_path=unique_users，unique_users.user_details.hits.hits._source但没有得到任何响应。我正在使用下面的函数来处理Elasticsearch查询。

  def query(options = {})

    aggregations = {}

    buckets = {}
    buckets_for_unique_users buckets, aggregations
    buckets_for_new_users buckets, aggregations
    buckets_for_high_rollers buckets, aggregations

    filters = []
    filters << time_filter(options)
    filters << restaurant_filter(options) if options[:restaurant_id]
    filters << channel_filter(options) if options[:channel_id]

    query = {
      query: { bool: { filter: filters } },
      aggregations: buckets
    }
    query
  end

谁能告诉我哪里做错了。

Answer 1

将“\u source”与请求中所需的属性一起使用。这将帮助您仅获取指定的字段。

https://www.elastic.co/guide/en/elasticsearch/reference/current/search-request-source-filtering.html