持有一个物理键，然后使用awt.robot在Java中自动按下相同的键

Question

我在我的程序中使用JNativeHook来检测程序之外的全局键程。这就是我需要完成的：

// These are the global variables
// ...
Robot robot;  // Initialized in the constructor
// ...
boolean spaceDown = false;
boolean activeThread = false;

private void pressSpace(){

    robot.keyPress(KeyEvent.VK_SPACE);
    robot.delay(20);
    robot.keyRelease(KeyEvent.VK_SPACE);
    robot.delay(30);

    System.out.println("Robot - Press/Release");

}

private void executeThread(){

    new Thread(){
        public void run(){
            while(spaceDown){
                pressSpace();
            }
            activeThread = false;
        }
    }.start();

}

public void nativeKeyPressed(NativeKeyEvent e){

    if(e.getKeyCode() == NativeKeyEvent.VC_SPACE){

        System.out.println("Physical - Pressed");

        activeThread = true;
        spaceDown = true;
        if(activeThread){
            executeThread();
        }
    }

}
public void nativeKeyReleased(NativeKeyEvent e){

    if(e.getKeyCode() == NativeKeyEvent.VC_SPACE){
        System.out.println("Physical - Released");
        spaceDown = false;
    }

}

...
Physical - Pressed
Physical - Released
Robot - Press/Release
Physical - Pressed
Physical - Released
Robot - Press/Release
...

Answer 1

我不知道你为什么要这么做...当你按住一个键时，在重复延迟过去后，你基本上得到一个键，即使在重复率下，直到你释放。如果要模拟按键弹回，即按键先按下，然后释放，而不是重复按键按下事件：

// These are the global variables
public void nativeKeyPressed(NativeKeyEvent e){

    if(e.getKeyCode() == NativeKeyEvent.VC_SPACE){

        System.out.println("Physical - Pressed");

        // This should produce a key release event.
        GlobalScreen.postNativeEvent(new NativeKeyEvent(
            NativeKeyEvent.NATIVE_KEY_RELEASED, 
            e.getWhen(), 
            e.getModifiers(), 
            e.getRawCode(), 
            e.getKeyCode, 
            e.getKeyChar(), 
            e.getKeyLocation()));
    }

}

上面的示例有很多线程安全问题，这可能是问题的原因。