刷新单个剑道网格行

Question

有没有一种方法可以在不刷新整个数据源或使用jQuery为每个单元格设置值的情况下刷新单个剑道网格行？

Answer 1

我找到了一种方法来更新网格dataSource并在网格中显示，而无需刷新所有网格。例如，您有一个选定的行，您想更改列“名称”值。

//the grid
var grid = $('#myGrid').data('kendoGrid');    
// Access the row that is selected
var row = grid.select();
//gets the dataItem
var dataItem = grid.dataItem(row);
//sets the dataItem   
dataItem.name = 'Joe';
//generate a new row html
var rowHtml = grid.rowTemplate(dataItem);
//replace your old row html with the updated one
row.replaceWith(rowHtml);

Answer 2

数据。set实际上会刷新整个网格，并在某些情况下发送数据绑定事件。这是非常缓慢和不必要的。它还将折叠任何不理想的展开详图模板。

我建议您使用我编写的这个函数来更新剑道网格中的一行。

// Updates a single row in a kendo grid without firing a databound event.
// This is needed since otherwise the entire grid will be redrawn.
function kendoFastRedrawRow(grid, row) {
    var dataItem = grid.dataItem(row);

    var rowChildren = $(row).children('td[role="gridcell"]');

    for (var i = 0; i < grid.columns.length; i++) {

        var column = grid.columns[i];
        var template = column.template;
        var cell = rowChildren.eq(i);

        if (template !== undefined) {
            var kendoTemplate = kendo.template(template);

            // Render using template
            cell.html(kendoTemplate(dataItem));
        } else {
            var fieldValue = dataItem[column.field];

            var format = column.format;
            var values = column.values;

            if (values !== undefined && values != null) {
                // use the text value mappings (for enums)
                for (var j = 0; j < values.length; j++) {
                    var value = values[j];
                    if (value.value == fieldValue) {
                        cell.html(value.text);
                        break;
                    }
                }
            } else if (format !== undefined) {
                // use the format
                cell.html(kendo.format(format, fieldValue));
            } else {
                // Just dump the plain old value
                cell.html(fieldValue);
            }
        }
    }
}

例子：

// Get a reference to the grid
var grid = $("#my_grid").data("kendoGrid");

// Access the row that is selected
var select = grid.select();
// and now the data
var data = grid.dataItem(select);

// Update any values that you want to
data.symbol = newValue;
data.symbol2 = newValue2;
...

// Redraw only the single row in question which needs updating
kendoFastRedrawRow(grid, select);

// Then if you want to call your own databound event to do any funky post processing:
myDataBoundEvent.apply(grid);

Answer 3

如何定义要更新的行？我将假设这是您选择的行，并且正在更新的列的名称是symbol。

js prettyprint-override">// Get a reference to the grid
var grid = $("#my_grid").data("kendoGrid");

// Access the row that is selected
var select = grid.select();
// and now the data
var data = grid.dataItem(select);
// update the column `symbol` and set its value to `HPQ`
data.set("symbol", "HPQ");

请记住，数据源的内容是一个可观察的对象，这意味着您可以使用集对其进行更新，并且更改应该神奇地反映在网格中。