Spring Jpa存储库引发的异常未被异常处理程序@Controller通知捕获

Question

下面是我在Spring boot中的ExceptionHandler类

@RestControllerAdvice
public class CustomResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {


@ExceptionHandler({InvalidRequestException.class, PropertyReferenceException.class})
public final ResponseEntity<ExceptionDetails> handleInvalidRequestException(InvalidRequestException ex, WebRequest request) {
    ExceptionDetails details = new ExceptionDetails(ex.getMessage(),request.getDescription(false), new Date());
    return new ResponseEntity<ExceptionDetails>(details, HttpStatus.BAD_REQUEST);

}

@Override
public Page<Segment> listSegment(int pageNum, int size, String sortBy, String direction, String app) {
        log.info("Starting to query the segment list");
        Pageable pageable = createPageRequest(size, pageNum, sortBy, direction);
        Pageable pageable = new PageRequest(page, size, dir, sortBy);
        Page<Segment> resultPage = segmentRepository.findByApp(app,pageable);
        if(pageNum > resultPage.getTotalPages() || resultPage.getContent().isEmpty()) {
            log.info("No segment present");
            throw new ResourceNotFoundException("No Segment Present");
        }

        log.info("Total segment successfully fetched is: "+resultPage.getContent().size());
        if(resultPage.hasNext())
            return new Page<>(resultPage.getContent(), true);
        else
            return new Page<>(resultPage.getContent());
    }

Answer 1

问题是以下行之间不匹配:@exceptionHandler（{InvalidRequestException.class,PropertyReferenceException.class}）&方法签名HandleInvalidRequestException（InvalidRequestException ex,WebRequest request）。

您将此方法注释为处理两个异常，但在方法参数中只指定了一个异常&该异常是一个非常特殊的异常，因此为InvalidRequestException调用该异常。如果希望两个异常都匹配到相同的方法，则方法参数必须是两个异常的父类。

您要么需要按照slimane的回答更改方法，要么有两个处理程序方法--每个异常一个。

(&A)

@ExceptionHandler（{PropertyReferenceException.class}）handlePropertyReferenceException（PropertyReferenceException ex,WebRequest request）