如何对Jackson JsonSerializer和JsonDeserializer进行单元测试

Question

我已经为我的应用程序编写了自定义的JsonSerializer和JsonDeserializer。现在我想为它们编写一些单元测试。

Answer 1

JSONSerializer

这个示例是序列化localdatetime，但是可以用所需的类型替换它。

@Test
public void serialises_LocalDateTime() throws JsonProcessingException, IOException {
    Writer jsonWriter = new StringWriter();
    JsonGenerator jsonGenerator = new JsonFactory().createGenerator(jsonWriter);
    SerializerProvider serializerProvider = new ObjectMapper().getSerializerProvider();
    new LocalDateTimeJsonSerializer().serialize(LocalDateTime.of(2000, Month.JANUARY, 1, 0, 0), jsonGenerator, serializerProvider);
    jsonGenerator.flush();
    assertThat(jsonWriter.toString(), is(equalTo("\"2000-01-01T00:00:00\"")));
}

JsonDeserializer

    private ObjectMapper mapper;
    private CustomerNumberDeserialiser deserializer;

    @Before
    public void setup() {
        mapper = new ObjectMapper();
        deserializer = new CustomerNumberDeserialiser();
    }

    @Test
    public void floating_point_string_deserialises_to_Double_value() {
        String json = String.format("{\"value\":%s}", "\"1.1\"");
        Number deserialisedNumber = deserialiseNumber(json);
        assertThat(deserialisedNumber, instanceOf(Double.class));
        assertThat(deserialisedNumber, is(equalTo(1.1d)));
    }

    @SneakyThrows({JsonParseException.class, IOException.class})
    private Number deserialiseNumber(String json) {
        InputStream stream = new ByteArrayInputStream(json.getBytes(StandardCharsets.UTF_8));
        JsonParser parser = mapper.getFactory().createParser(stream);
        DeserializationContext ctxt = mapper.getDeserializationContext();
        parser.nextToken();
        parser.nextToken();
        parser.nextToken();
        return deserializer.deserialize(parser, ctxt);
    }

为了绕过这个问题，我使用了这个SO答案来窥探final类deserializationcontext:

DeserializationContext ctxt = spy(mapper.getDeserializationContext());
doReturn(true).when(ctxt).isEnabled(any(MapperFeature.class));

我感觉一定有更好的方法，所以如果你有的话请评论一下。