如何在改版2中解析json下面的内容？

Question

{“状态”：true,“消息”：“welcome jaymin”,“数据”：{“ID”：1,“name”：“jaymin”,“email”：“[e-mail]”,“mobile”：“123456”}}

Answer 1

您可以在creating Revovit service中添加GsonFactory或can JacksonFactory,并可以使用此链接http://www.jsonschema2pojo.org/创建一个pojo类,通过它可以解析数据。我已经将您的JSON转换为Gson格式的java类，您可以在android中使用它来解析数据。

   -----------------------------------com.example.Data.java----------------------- 
   ------------

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Data {

@SerializedName("id")
@Expose
private Integer id;
@SerializedName("name")
@Expose
private String name;
@SerializedName("email")
@Expose
private String email;
@SerializedName("mobile")
@Expose
private String mobile;

public Integer getId() {
return id;
}

public void setId(Integer id) {
this.id = id;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getEmail() {
return email;
}

public void setEmail(String email) {
this.email = email;
}

public String getMobile() {
return mobile;
}

public void setMobile(String mobile) {
this.mobile = mobile;
}

}
-----------------------------------com.example.FollowersResponse.java-----------------------------------

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class FollowersResponse {

@SerializedName("status")
@Expose
private Boolean status;
@SerializedName("message")
@Expose
private String message;
@SerializedName("data")
@Expose
private Data data;

public Boolean getStatus() {
return status;
}

public void setStatus(Boolean status) {
this.status = status;
}

public String getMessage() {
return message;
}

public void setMessage(String message) {
this.message = message;
}

public Data getData() {
return data;
}

public void setData(Data data) {
this.data = data;
}

}