改版2.0如何解析嵌套JSON对象？

Question

{
        "title": "Recent Uploads tagged android",
        "link": "https://www.flickr.com/photos/tags/android/",
        "description": "",
        "modified": "2015-10-05T05:30:01Z",
        "generator": "https://www.flickr.com/",
        "items": [
        {
            "title": ...
            "link": ...
            "media": {"m":"This is the value I want to get:)"}
            "description": ...
            "published": ...
            "author": ...
            "author_id": ...
            "tags": ...
        },
        {...},
        ...
        ]
}

1. 编写我自己的JSON转换器工厂，它扩展converter.factory.
2. 以字符串类型返回原始响应，并自己解析。但是根据我最初的研究，从改型2.0中得到原始的响应并不容易。Retrofit 2.0似乎坚持在将响应传递给我之前将其转换为某个内容，而且Retrofit没有提供自己的StringConverter。（我可能错了~)

Update：我们实际上可以通过将JSONElement设置为HTTP API接口的pojo，并使用Retrofit提供的GSONConverter作为转换器来获得原始响应。

Answer 1

假设完整的JSON如下所示

{
  "title": "Recent Uploads tagged android",
  "link": "https://www.flickr.com/photos/tags/android/",
  "description": "",
  "modified": "2015-10-05T05:30:01Z",
  "generator": "https://www.flickr.com/",
  "items": [
    {
      "member1": "memeber value",
      "member2": "member value"
    },
    {
      "member1": "memeber value",
      "member2": "member value"
    }
  ]
}

所以Pojo类将是

public class MainPojo {
    private String title; 
    private String description;
    private String link;
    private String generator;
    private String modified;
    private ArrayList<Items> items;

    // Getters setters
}

public class Items {
    private String member2;
    private String member1;

    // Getters setters
}

注意：对于您的JSON来说，这是类似的解决方案。如果JSON有其他键，则可以更改items.java的成员。

public class Items {
    private String tags;
    private String author;
    private String title;
    private String description;
    private String link;
    private String author_id;
    private String published;
    private Media media;

    // Getters and Setters
}

public class Media {
    private String m;
    // Getters and Setters
}