Java无法解析嵌套的json对象

Question

下面是一些示例代码：

import org.json.JSONObject;

String k = "{\"root1\":\"{\\\"key1\\\":\\\"val1\\\",\\\"key2\\\":1,\\\"key3\\\":null}\",\"root2\":\"OTHERS\",\"root3\":1}";
JSONObject obj = new JSONObject(str);
System.out.println(obj);

/* 
here I want to do something like:
JSONObject innerObj = (JSONObject) obj.get("root1");
String k1 = innerObj.get("key1");

Also, should work with nested inner objects, so for example, should be able to do:
String k4 = innerObj.get("key1.innerKey1");
*/

{"root1":"{\"key1\":\"val1\",\"key2\":1,\"key3\":null}","root2":"OTHERS","root3":1}

On doing JSONObject innerObj = （JSONObject） obj.get（“root1”）;- 它给出：

线程“main”中出现异常Java . lang . classcastexception:Java . lang . string不能转换为org.json.JSONObject

我尝试了Gson、JSONParser-但仍然无法做到...

注意：字符串“k”的解析工作正常，因为obj已正确填充并打印出来。当我尝试访问这个对象中的对象时，它失败了：JSONObject innerObj=（JSONObject）obj.get（“root1”）；

Answer 1

请检查这个-

public static void main(String[] args) {

    String k ="{\"root1\":{\"key1\":\"val1\",\"key2\":1,\"key3\":null},\"root2\":\"OTHERS\",\"root3\":1}";
    JSONObject obj = new JSONObject(k);
    System.out.println(obj);
     
    //here I want to do something like:
    JSONObject innerObj = (JSONObject) obj.get("root1");
    Object k1 =  innerObj.get("key1");
    System.out.println(k1);
    Object k2 =  innerObj.get("key2");
    System.out.println(k2);
    Object k3 =  innerObj.get("key3");
    System.out.println(k3);
    
    System.out.println(obj.get("root2"));
    System.out.println(obj.get("root3"));
}

输出-

{"root1":{"key1":"val1","key2":1,"key3":null},"root2":"OTHERS","root3":1}
val1
1
null
OTHERS
1

Answer 2

在apache commons文本库中有一个实用工具StringEscapeUtils类用于这种翻译。应用它将删除< code>root1值周围多余的双引号。

将此共享资源文本 jar 依赖项添加到您的项目中。

用法-

String k = "{\"root1\":\"{\\\"key1\\\":\\\"val1\\\",\\\"key2\\\":1,\\\"key3\\\":null}\",\"root2\":\"OTHERS\",\"root3\":1}";

// add this line
String unescapedJsonString = StringEscapeUtils.unescapeJson(k);

 // pass new json string to Json library
JSONObject obj = new JSONObject(unescapedJsonString);