带有两列静态编程语言的RadioGroup

Question

我有两个单选组（组1和组2），分别包含3个单选按钮。我用这个准则把左右两列分开，各占一半。由于两个无线组是分开的，当用户单击组1时，我希望清除组2中的选定项（如果有）。任何想法都可以做到，因为我是由Kotlin编写的，所以我在stackoverflow ConstraintLayout、RadioGroup和RadioButton RadioGroup的两列中找到了一些示例，其中两列有十个单选按钮，因为该示例是用JAVA编写的，但我无法在Kotlin代码中应用。我是Kotlin和Java的新手，我正在使用Android Studio的“导航抽屉活动”，并将代码应用到“Fragment.kt”中，有人对此有想法吗？谢谢

这是我在MainA中的静态编程语言编码ctivity.ktval val listener2--

package com.example.pain_testing

import androidx.appcompat.app.AppCompatActivity
import android.os.Bundle
import android.widget.RadioGroup
import android.util.Log


class MainActivity : AppCompatActivity() {

val rg1 = findViewById(R.id.radioGroup1) as RadioGroup
val rg2 = findViewById(R.id.radioGroup2) as RadioGroup

override fun onCreate(savedInstanceState: Bundle?) {
    super.onCreate(savedInstanceState)
    setContentView(R.layout.activity_main)
    rg1.clearCheck(); // this is so we can start fresh, with no selection on both RadioGroups
    rg2.clearCheck();
    rg1.setOnCheckedChangeListener(listener1); //apply onCheckChangeListener
    rg2.setOnCheckedChangeListener(listener2);
}

private val listener1 = object : RadioGroup.OnCheckedChangeListener {

    override fun onCheckedChanged(group: RadioGroup, checkedId: Int) {
        if (checkedId != -1) {
            rg2.setOnCheckedChangeListener(null) // remove the listener before clearing so we don't throw that stackoverflow exception(like Vladimir Volodin pointed out)
            rg2.clearCheck() // clear the second RadioGroup!
            rg2.setOnCheckedChangeListener(listener2) //reset the listener
            Log.e("XXX2", "do the work")
        }
    }
}

private val listener2 = object : RadioGroup.OnCheckedChangeListener {

    override fun onCheckedChanged(group: RadioGroup, checkedId: Int) {
        if (checkedId != -1) {
            rg1.setOnCheckedChangeListener(null)
            rg1.clearCheck()
            rg1.setOnCheckedChangeListener(listener1)
            Log.e("XXX2", "do the work")
        }
    }
}

}

Answer 1

private lateinit var radioGroup1: RadioGroup
private lateinit var radioGroup2: RadioGroup
private var radioGroupBlock: Boolean = false

    ...

    radioGroup1 = view.findViewById(R.id.radioGroup_1)
    radioGroup2 = view.findViewById(R.id.radioGroup_2)

    ...

    radioGroup1.setOnCheckedChangeListener({ group, checkedId ->
        if (radioGroupBlock)
            return@setOnCheckedChangeListener
        val radio: RadioButton = view.findViewById(checkedId)
        toast(" On checked change : ${radio.text}")
        var id: Int = radioGroup2.checkedRadioButtonId
        if (id!=-1){
            radioGroupBlock = true
            radioGroup2.clearCheck()
            radioGroupBlock = false
        }
    })

    radioGroup2.setOnCheckedChangeListener({ group, checkedId ->
        if (radioGroupBlock)
            return@setOnCheckedChangeListener
        val radio: RadioButton = view.findViewById(checkedId)
        toast(" On checked change : ${radio.text}")
        var id: Int = radioGroup1.checkedRadioButtonId
        if (id!=-1){
            radioGroupBlock = true
            radioGroup1.clearCheck()
            radioGroupBlock = false
        }

    })

Answer 2

您可以执行以下操作：

首先初始化两个无线电组，如下所示：

val rg1 = findViewById(R.id.radioGroup1) as RadioGroup
val rg2 = findViewById(R.id.radioGroup2) as RadioGroup
rg1.clearCheck(); // this is so we can start fresh, with no selection on both RadioGroups
rg2.clearCheck();
rg1.setOnCheckedChangeListener(listener1); //apply onCheckChangeListener
rg2.setOnCheckedChangeListener(listener2); 

然后创建onCheckChangeListener：

private val listener1 = object : OnCheckedChangeListener() {

fun onCheckedChanged(group: RadioGroup, checkedId: Int) {
    if (checkedId != -1) {
        rg2.setOnCheckedChangeListener(null) // remove the listener before clearing so we don't throw that stackoverflow exception(like Vladimir Volodin pointed out)
        rg2.clearCheck() // clear the second RadioGroup!
        rg2.setOnCheckedChangeListener(listener2) //reset the listener
        Log.e("XXX2", "do the work")
    }
}

Answer 3

只需在更改侦听器中清除：

radioGroup1.setOnCheckedChangeListener { _, _ -> 
    radioGroup2.clearCheck()
}