java-map遍历列表并跳过前N个条目

Question

我对Java还很陌生，所以请你宽大一点。我有一张地图，地图 。我需要遍历这些值，跳过前N个索引，并将剩余的内容添加到另一个列表中进行处理。

Key:   foo
Value: [id=001, name=Fred, job=Mailman, age=51],
       [id=002, name=Johan, job=Musician, age=335],
       [id=003, name=Alice, job=Finance, age=49],
       [id=004, name=Marcus, job=Developer, age=41]

List<Object> finalList = new ArrayList<Object>();
List<Object> sortedList = new ArrayList<Object>();

Map<String, List<Object> map = getMapFn();

for(List<Object> anotherList : map.values()) {
   Collections.reverse(anotherList);
   sortedList = anotherList;

   for(Object o : sortedList) {
      int skipN = N;

      for(int i = 0; i < sortedList.size(); i++) {
         if(i < skipN) {
            continue;
         }
      }
      finalList.add(o);
   }
}

最终目标：

If N=2,
finalList = [id=003, name=Alice, job=Finance, age=49],
[id=004, name=Marcus, job=Developer, age=41]

Answer 1

在您的代码中，sortedList中的项将始终添加到finalList中

   int skipN = N;
   int index = 0;
   for(Object o : sortedList) {
      if(index<skipN){
          index++;
          contine;
      }
      index++;
      finalList.add(o);
   }

或者使用JDK1.8流

sortedList.stream().skip(skipN).collect(Collectors.toList())