令牌“else”语法错误，请删除此令牌

Question

import java.util.Scanner;
public class CountryDetails {
  public static void main(String [] args) {
    Scanner input=new Scanner(System.in);
    System.out.println("Enter any of the following integers to see details of the corresponding country:(1, 36, 57, 94, 250, 269, 354, 376, 597, 678, 962, 992)");
    //prompt reader to enter a number
    int code=input.nextInt();

    int x;
    x=input.nextInt();
    if ((x!=1)&&(x!=36)&&(x!=57)&&(x!=94)&&(x!=250)&&(x!=269)&&(x!=354)&&(x!=376)&&(x!=597)&&(x!=678)&&(x!=962)&&(x!=992)); {
      System.out.println("You did not enter one of the possible integers.");
    }

    else if (x==1) { //error is here
      System.out.println("Enter amount in US dollars:"); //prompt reader to enter US dollars
      double dollars = input.nextDouble(); //reading input
      double exchangeRate= dollars*45.72;

      //display results
      System.out.println ("1 is the Country Calling Code for the Dominican Republic, which is located in the Americas");
      System.out.println (+dollars+ " is equivalent to " +exchangeRate+ "Dominican Pesos.");
    }

谢谢！！

Answer 1

下面是一个很好的教程，介绍if和if-else语句如何在Java中工作。考虑Java中的以下两种情况。

案例1

if (boolean-expression)
    statement

案例2

if (boolean-expression-1)
{
        statement-1
        statement-11
        statement-111
}
else
{
        statement-2
        statement-22
}

if ((x!=1)&&(x!=36)&&(x!=57)&&(x!=94)&&(x!=250)&&(x!=269)&&(x!=354)&&(x!=376)&&(x!=597)&&(x!=678)&&(x!=962)&&(x!=992)) {
      System.out.println("You did not enter one of the possible integers.");
    }