swagger：使用路径参数发出

Question

如果我对此进行深入研究，我会看到以下内容：

Details
 Object
 swaggerError: Object
 errors: Array [1]
 0: Object
code:  "MISSING_API_PATH_PARAMETER"
message:  "API requires path parameter but it is not defined: id"
data:  "/v1/customers/{id}/summary"
 path: Array [2]
 warnings: Array [0]

Answer 1

基本上，您是通过使用路径模板声明一个包含路径参数的路径。在本例中，{id}声明一个名为id的路径参数。

当您声明这样一个路径时，意味着您必须声明该路径参数作为操作的一部分。

看一下这个YAML示例：

  /pets/{id}:
    get:
      description: Returns a user based on a single ID, if the user does not have access to the pet
      operationId: findPetById
      produces:
        - application/json
        - application/xml
        - text/xml
        - text/html
      parameters:
        - name: id
          in: path
          description: ID of pet to fetch
          required: true
          type: integer
          format: int64
      responses:
        '200':
          description: pet response
          schema:
            $ref: '#/definitions/pet'
        default:
          description: unexpected error
          schema:
            $ref: '#/definitions/errorModel'