无法在ios-appium上从下向上滑动

Question

我想在ios上设置wifi状态，为此，我需要从控制中心底部向上滑动。

    dimension = driverWrapper.getIosDriver().manage().window().getSize();
    int middleX = dimension.getWidth() / 2;
    int y = dimension.getHeight();
   driverWrapper.getIosDriver().swipe(middleX,y-10,middleX,150,600);

在我将java客户端升级到4.0.0和appium升级到1.5.2之前，它工作正常。

我得到一个错误：error:VerboseError:point不在屏幕范围内

记录如下：

[debug] [UIAuto] Socket data received (49 bytes)
[debug] [UIAuto] Got result from instruments: {"status":0,"value":{"width":320,"height":568}}
[MJSONWP] Responding to client with driver.getWindowSize() result: {"width":320,"height":568}
[HTTP] <-- GET /wd/hub/session/31411e39-f408-418f-b9b8-e28b80ba1b35/window/current/size 200 1071 ms - 98 
[HTTP] --> POST /wd/hub/session/31411e39-f408-418f-b9b8-e28b80ba1b35/touch/perform {"actions":[{"action":"press","options":{"x":160,"y":558}},{"action":"wait","options":{"ms":100}},{"action":"moveTo","options":{"x":160,"y":284}},{"action":"release","options":{}}]}
[MJSONWP] Calling AppiumDriver.performTouch() with args: [[{"action":"press","options":{"x":160,"y":558}},{"action":"wait","options":{"ms":100}},{"action":"moveTo","options":{"x":160,"y":284}},{"action":"...
[debug] [iOS] Executing iOS command 'performTouch'
[debug] [UIAuto] Sending command to instruments: target.touch([{"touch":[{"x":160,"y":558}],"time":0.2},{"touch":[{"x":160,"y":558}],"time":0.30000000000000004},{"touch":[{"x":320,"y":842}],"time":0.5}])

[debug] [Instruments] [INST] 2016-06-19 07:39:13 +0000 Debug: Got new command 6 from instruments: target.touch([{"touch":[{"x":160,"y":558}],"time":0.2},{"touch":[{"x":160,"y":558}],"time":0.30000000000000004},{"touch":[{"x":320,"y":842}],"time":0.5}])

[debug] [Instruments] [INST] 2016-06-19 07:39:13 +0000 Debug: evaluating target.touch([{"touch":[{"x":160,"y":558}],"time":0.2},{"touch":[{"x":160,"y":558}],"time":0.30000000000000004},{"touch":[{"x":320,"y":842}],"time":0.5}])

[debug] [Instruments] [INST] 2016-06-19 07:39:13 +0000 Debug: target.touch(__NSCFArray)

[debug] [Instruments] [INST] 2016-06-19 07:39:13 +0000 Debug: point is not within the bounds of the screen

知道是怎么回事吗？

谢谢

Answer 1

带Appium 1.6.5的iOS10 Python版本：

def swipe_up(self):

logging.info("swipe up")
sleep(1)
window_size = self.driver.get_window_size()  # this returns dictionary
sleep(1)
el = self.driver.find_element(*self.configuration.CommonScreen.WEB_VIEW)
action = TouchAction(self.driver)
sleep(1)
start_x = window_size["width"] * 0.5
start_y = window_size["height"]
end_x = window_size["width"] * 0.5
end_y = window_size["height"] * 0.5
action.press(el, start_x, start_y).wait(100).move_to(el, end_x, end_y).release().perform()
sleep(1)

对于iOS9，您需要将等待更改为1000。

Answer 2

JavascriptExecutor executor = driver;

executor.executeScript(
    "target.frontMostApp().mainWindow().dragInsideWithOptions({startOffset:{x:0.5, y:0.1}, endOffset:{x:0.5, y:0.7}, duration:0.8});");

检查这是否有效。。如果没有，则尝试进一步减小y:0.01。

Answer 3

滑动方法条件（仅适用于IOS）以避免此错误

>

0

0个

务实的永久解决方案

为了简化我们的日常生活，写下这样一个函数

public void swipeFinger(startx, starty, endx, endy, duration) {
   driver.swipe(startx, starty, startx - endx, starty - endy, duration);
}

RCA for Error:VerboseError:点不在屏幕范围内

问题是驱动程序的endx和endy输入参数。对于IOS，滑动方法的实现方式不同。

它实际上是DOS和DeltayIOS。看看这个图像并考虑你的手指在原点（两个轴的交点）。

如果您想向下或右侧滑动手指，您需要传递正endx和endy正值，如果您想向下向上或从右向左滑动，您需要传递您想要滑动手指的像素的负值。

20像素右扫

驱动程序。轻扫（startx、starty、20、0、持续时间）

因为您不想在垂直方向上移动手指，所以y始终为零！

20像素向下滑动

驱动程序。滑动（开始、开始、0、20、持续时间）

因为您不想在水平方向上移动手指，所以x始终为零！

现在向上和向左滑动操作

20像素向上滑动动作

驱动程序。轻扫（startx，starty，0，-20，持续时间）

20像素左划动作

driver.swipe（starx， starty，-20,0，持续时间）