Appium 1.6，iOS10：在特定元素上向左滑动

Question

我试图使用Appium 1.6在iOS 10上的某个特定元素上向左滑动，以显示删除按钮。

触摸操作和向左滑动的滑动代码在appium 1.4中运行良好，但问题是在我们迁移到appium 1.6之后才出现的。

非常感谢您的帮助

Answer 1

试试这个代码。调用flick_left并传递WebElement。

flick_left（元素）

public void flick_left(WebElement flick_element) {
        Point location = flick_element.getLocation();
        Dimension size = flick_element.getSize();

            int flick_x, flick_y, flick_start_x, flick_end_x,flick_start_y,flick_end_y;  

            flick_x =size.getWidth();       
            flick_y = location.y + (size.getHeight()/2);

            flick_start_x = flick_x - (int)((double)flick_x*0.25);
            flick_end_x = flick_x -(int)((double)flick_x*0.55);
            swipe(flick_start_x, flick_y, flick_end_x, flick_y,-200);

}



public void swipe(int swipe_start_x, int swipe_start_y, int swipe_end_x, int swipe_end_y,int duration){

        int x = swipe_start_x;
        int y = swipe_start_y;
        int x_travel =  swipe_end_x-swipe_start_x;
        int y_travel =  swipe_end_y-swipe_start_y;
        TouchAction action1 = new TouchAction(driver).press(x,y).waitAction(duration).moveTo(x_travel, y_travel).release();
        action1.perform();


    }

Answer 2

public void swipe(String direction, int offset, int time) {

        int y = appiumDriver.manage().window().getSize().getHeight();
        int x = appiumDriver.manage().window().getSize().getWidth();
        TouchAction touchAction = new TouchAction(appiumDriver);
        System.out.println(x+" "+y);
        System.out.println("Entering swipe");
        if("right".equalsIgnoreCase(direction))
        {
            System.out.println("Swipe Right");
            touchAction.press(x-offset, y/2).moveTo(-(x-(2*offset)), 0).release().perform();
        }else if("left".equalsIgnoreCase(direction)){
            System.out.println("Swipe Left");
            touchAction.press(offset, y/2).moveTo((x-(2*offset)), 0).release().perform();
        }else if("up".equalsIgnoreCase(direction)){
            System.out.println("Swipe Up");
            touchAction.press(x/2, offset).moveTo(0, y-(2*offset)).release().perform();
        }else if("down".equalsIgnoreCase(direction)){
            System.out.println("Swipe Down");
            touchAction.press(x/2, y-offset).moveTo(0, -(y-(2*offset))).release().perform();
        }
        try {
            Thread.sleep(2000);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

Answer 3

我也有同样的问题，现在我找到了解决办法。

细节：

 Appium 1.6.4 beta 
 Java-Client-5.x beta

Appium 1.6.x-已删除滑动，我们必须为滑动创建自己的TouchAction，因为waitAction（）使用负值将执行快速滑动操作。e、 g等待行动（-200）。

TouchAction action1 = new TouchAction(driver).press(x,y).waitAction(-200).moveTo(x_travel, y_travel).release();
        action1.perform();

发布你的反馈。