如何实现基于窗格的自定义JavaFX控件

Question

我看到扩展区域或控件是可能的，这是推荐的？需要什么才能将大小调整和布局委派给窗格？

public class BasePaneControl extends Control {
    private final Pane pane;

    public BasePaneControl(Pane pane) {
        this.pane = pane;
        getChildren().add(pane);
    }

    // What do I need to delegate here to the pane to get sizing
    // to affect and be calculated by the pane?
}

public class MyControl extends BasePaneControl {
    private final GridPane gp = new GridPane();
    public MyControl() {
        super(gp);
        gp.add(new TextField(), 0, 0);
        gp.add(new CheckBox(), 0, 1);
        gp.add(new Button("Whatever"), 0, 2);
    }

    // some methods to manage how the control works.
}

我需要帮助实现上面的basePaneControl。

Answer 1

扩展区域，并重写layoutChildren方法。

您可以使用region.snappedtopInset（）方法（以及bottom、left和right）获取BasePaneControl的位置。然后根据可能是BasePaneControl一部分的其他组件进行计算以定位您希望窗格的位置。

知道窗格的位置后，调用ResizereLocate。

/**
 * Invoked during the layout pass to layout this node and all its content.
 */
@Override protected void layoutChildren() {
    // dimensions of this region
    final double width = getWidth();
    final double height = getHeight();

    // coordinates for placing pane
    double top = snappedTopInset();
    double left = snappedLeftInset();
    double bottom = snappedBottomInset();
    double right = snappedRightInset();

    // adjust dimensions for pane based on any nodes that are part of BasePaneControl
    top += titleLabel.getHeight();
    left += someOtherNode.getWidth();

    // layout pane
    pane.resizeRelocate(left,top,width-left-right,height-top-bottom);
}