如何在php中一次移动已上载的多个图像

Question

我正在尝试上载3个图像字段，将它们存储在我的数据库中，并将上载的文件移动到文件夹中。

目前，“image1”、“image2”、“image3”、“image4”字段正在插入MySQL数据库，但只有“image1”正在上载并移动到我的文件夹中。

这是我的密码：

if(isset($_POST['submit'])){
  $pro_image1 = $_FILES['image1']['name'];
  $pro_image2 = $_FILES['image2']['name'];
  $pro_image3 = $_FILES['image3']['name'];
  $pro_image4 = $_FILES['image4']['name'];
  $tmp_name   = $_FILES['image1']['tmp_name'];
  $tmp2_name  = $_FILES['image2']['tmp_name'];
  $tmp3_name  = $_FILES['image3']['tmp_name'];
  $tmp4_name  = $_FILES['image4']['tmp_name'];

  $pro_query = "INSERT INTO product(image1,image2,image3,image4) VALUES('$pro_image1','$pro_image2','$pro_image3','$pro_image4')";

  if(mysqli_query($con,$pro_query)){
    $msg = "<p class='pull-right' style='color:green;'> Product Added successfully</p>";
    $path = "images/$pro_image1";

    if(move_uploaded_file($tmp_name, $path)) {
      copy($path, "../$path");
    }

    if(move_uploaded_file($tmp2_name, $path)) {
      copy($path, "../$path");
    }

    if(move_uploaded_file($tmp3_name, $path)) {
      copy($path, "../$path");
    }

    if(move_uploaded_file($tmp4_name, $path)) {
      copy($path, "../$path");
    } elseif(!mysqli_query($con,$pro_query)) {
      $insert_error = "<p class='pull-right' style='color:red;>Product didn't added</p>";
    }
  }
}

<form action="" method="post" enctype="multipart/form-data"  class="form-font">
  <div class="col-md-6">
    <div class="form-group">
      <label>Image1</label>
      <input type="file" name="image1" class="form-control" required>
    </div>
    <div class="form-group">
      <label>Image2</label>
      <input type="file" name="image2" class="form-control" required>
    </div>
    <div class="form-group">
      <label>Image3</label>
      <input type="file" name="image3" class="form-control" required>
    </div>
    <div class="form-group">
      <label>Image4</label>
      <input type="file" name="image4" class="form-control" required>
    </div>
    <center>
      <input type='submit' name='submit' class='btn btn-success' value='Add Product'>
    </center>
  </div>
</form>

如何移动文件夹中的其他图像（“image2”、“image3”、“image4”）？
我在代码中犯了什么错误？你能解释一下我哪里做错了吗？

Answer 1

您只为image1定义了var$path——您需要在函数move\u upload\u file and copy的每个“if”块中更改此var。目前，对于所有图像，您仅使用image1的路径和文件名。

Answer 2

请覆盖您的$path变量，然后它将上传属性...

在if条件更改$path变量之前，如下面所示，或将变量更改为$path1、$path2、$path3。。

$path = "images/$pro_image1";
$path = "images/$pro_image2";
$path = "images/$pro_image3";

-

        if(isset($_POST['submit'])){
   $pro_image1 = $_FILES['image1']['name'];
        $pro_image2 = $_FILES['image2']['name'];
        $pro_image3 = $_FILES['image3']['name'];
        $pro_image4 = $_FILES['image4']['name'];
        $tmp_name = $_FILES['image1']['tmp_name'];
        $tmp2_name = $_FILES['image2']['tmp_name'];
        $tmp3_name = $_FILES['image3']['tmp_name'];
        $tmp4_name = $_FILES['image4']['tmp_name'];
$pro_query = "INSERT INTO product(image1,image2,image3,image4) VALUES('$pro_image1','$pro_image2','$pro_image3','$pro_image4')";
        if(mysqli_query($con,$pro_query)){
            $msg = "<p class='pull-right' style='color:green;'> Product Added successfully</p>";
            $path = "images/$pro_image1";
            if(move_uploaded_file($tmp_name, $path)){
                 copy($path, "../$path");
               }
               $path = "images/$pro_image2";
               if(move_uploaded_file($tmp2_name, $path)){
                 copy($path, "../$path");
               }
               $path = "images/$pro_image3";
               if(move_uploaded_file($tmp3_name, $path)){
                 copy($path, "../$path");
               }
               $path = "images/$pro_image4";
               if(move_uploaded_file($tmp4_name, $path)){
                 copy($path, "../$path");
               }
               elseif(!mysqli_query($con,$pro_query)){
            $insert_error = "<p class='pull-right' style='color:red;>Product didn't added</p>";
        }
    }
}

<form action="" method="post" enctype="multipart/form-data"  class="form-font">
    <div class="col-md-6">
       <div class="form-group">
                <label>Image1</label>
                <input type="file" name="image1" class="form-control" required>
                </div>
                <div class="form-group">
                <label>Image2</label>
                <input type="file" name="image2" class="form-control" required>
                </div>
                <div class="form-group">
                <label>Image3</label>
                <input type="file" name="image3" class="form-control" required>
                </div>
                <div class="form-group">
                <label>Image4</label>
                <input type="file" name="image4" class="form-control" required>
                </div>
<center><input type='submit' name='submit' class='btn btn-success' value='Add Product'></center>
            </form>

Answer 3

以下是您需要做的：

if(move_uploaded_file($tmp_name, $path)){
             copy($path, "images/$pro_image2");
           }
           if(move_uploaded_file($tmp2_name, $path)){
             copy($path, "images/$pro_image3");
           }if(move_uploaded_file($tmp3_name, $path)){
             copy($path, "images/$pro_image4");
           }if(move_uploaded_file($tmp4_name, $path)){
             //copy($path, "images/$path");
           }