Grep regex在排除关键字列表时查找重复字

Question

我有很多数据在一个目录，我想找到任何实例的双字不是数字。我从这里开始：

\b(\w+) \1\b

并将其扩展到包括我不希望在结果中出现的内容：

(?!(?:one|two|three|four|five|six|seven|eight|nine|oh|zero))\b(\w+) \1\b

 grep -Proh "\b(\w+) \1\b" | grep -Prohv "?(?:one|two|three|four|five|six|seven|eight|nine|oh|zero)"

要忽略的样本数据:
比重1点零零七

Answer 1

只要-p或-op就足够了。

$ grep -P '(?!(?:one|two|three|four|five|six|seven|eight|nine|oh|zero))\b(\w+) \1\b' file
today to evaluate for possibilities. doubt that that is occurring
$ grep -oP '(?!(?:one|two|three|four|five|six|seven|eight|nine|oh|zero))\b(\w+) \1\b' file
that that