如何使用逻辑运算符[重复]

Question

我已经尝试了所有的方法，如果你不选择“ST”，它会不断地在while循环中循环。我不知道该怎么办，如果有人能告诉我，那将非常有帮助。我在顶部添加了一些上下文代码；我只需要while循环的帮助。我正在使用while循环，因此如果他们没有选择给定的位置，他们必须重新选择。

这是我的密码：

pos = input("What Is Your Choice")

if pos == "ST":
    shot = 8
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 2
    print("Defending Is",defending)

if pos == "MID":
    shot = 6
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 4
    print("Defending Is",defending)

if pos == "DEF":
    shot = 2
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 4
    print("Pace Is",pace)
    defending = 8
    print("Defending Is",defending)

if pos == "GK":
    dive = 7
    dist = 8
    catch = 7

print(pos)

while pos != "ST" and "MID" and "DEF" and "GK" and "St" and "Mid" and 
"Def" and "Gk":
    print("What Position Do You Want To Play?")
    time.sleep(1)
    print("The Options Are..")
    time.sleep(1)
    print("ST (Striker)")
    time.sleep(1)
    print("MID (Midfielder)")
    time.sleep(1)
    print("DEF (Defender)")
    time.sleep(1)
    print("GK (Goalkeeper)")
    time.sleep(1)

pos = input("What Is Your Choice")

Answer 1

而循环永远不会结束，因为您的输入在外面。这是工作代码：

import time
pos = ""


while pos != "ST" and "MID" and "DEF" and "GK" and "St" and "Mid" and "Def" and "Gk":
    print("What Position Do You Want To Play?")
    time.sleep(1)
    print("The Options Are..")
    time.sleep(1)
    print("ST (Striker)")
    time.sleep(1)
    print("MID (Midfielder)")
    time.sleep(1)
    print("DEF (Defender)")
    time.sleep(1)
    print("GK (Goalkeeper)")
    time.sleep(1)

    pos = input("What Is Your Choice")
    break


if pos == "ST":
    shot = 8
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 2
    print("Defending Is",defending)

if pos == "MID":
    shot = 6
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 6
    print("Pace Is",pace)
    defending = 4
    print("Defending Is",defending)

if pos == "DEF":
    shot = 2
    print("Shot Is",shot)
    passing = 6
    print("Passing Is",passing)
    pace = 4
    print("Pace Is",pace)
    defending = 8
    print("Defending Is",defending)

if pos == "GK":
    dive = 7
    dist = 8
    catch = 7

    print(pos)

您必须使用“”进行选择，因为它是一个字符串

Answer 2

!= 仅适用于直接在其前面和后面列出的项目（不使用parens和诸如此类的操作）。因此，在您的示例中，while循环表示“当位置不等于ST，MID为true，DEF为true，DK为true，MID为true，DEF为true，Gk为true时，执行您的语句。

要告诉你的程序在位置不等于ST，也不等于MID，也不等于DEF等的情况下执行time循环，你必须明确地拼写出来-

while pos != "ST" and pos != "MID" and ... and post != "Gk"

Answer 3

这部分是错误的：

while pos != "ST" and "MID" and "DEF" and "GK" and "St" and "Mid" and "Def" and "Gk":

pos！="ST"被计算，其余的字符串不与任何东西进行比较。事实上，这部分的评价是：

while (pos != "ST") and ("MID") and ("DEF") and ("GK") and ("St") and ("Mid") and ("Def") and ("Gk"):

非空字符串总是True，因此只要pos！="ST"是True，它永远不会离开循环。你可能想做的是：

while pos != "ST" and pos != "MID" and pos != "DEF" and pos != "GK" and pos != "St" and pos != "Mid" and pos != "Def" and pos != "Gk":

但是，正如其中一条评论所指出的，您可以在中使用：

while pos not in {"ST", "MID", "DEF", "GK", "St", "Mid", "Def", "Gk"}:

注意，我在这里使用了一个集合，因为它们提供了更有效的成员资格测试。在这个小例子中可能没什么大不了的，但是它是一个更好的选择。