如何打印差异为1的列表中元素的间隔？[闭门]

Question

我在下面写的代码保存了进程在ArrayList中拥有cpu时的时间戳。如果（timeStamps.get（i）-时间戳。get（i-1）==1）进程当时拥有CPU。例如，如果列表如下所示：

List[0] = 5
List[1] = 6
List[2] = 7
List[3] = 10
List[4] = 11
List[5] = 12
List[6] = 20
List[7] = 21
List[8] = 22

控制台的输出应该是这样的：

CPU time: 3ms
Non-CPU time: 2ms
CPU time: 3ms
Non-CPU time: 7ms
CPU time: 3ms

我怎么能这么做呢？这就是我迄今为止所做的

long ms = 1000000;
ArrayList<Long> timeStamps = new ArrayList<Long>();
long startStamp = System.nanoTime()/ms;

timeStamps.add(startStamp);

for (int i = 1; i > 0; i++) {
    long nextStamp = System.nanoTime()/ms;
    if(nextStamp - startStamp >= 1) {
        timeStamps.add(nextStamp);
        startStamp = nextStamp;
    }
    if(timeStamps.size() == 20) {
        i = -10;
    }
}

Answer 1

我解决了：）这就是我的意思，很抱歉，我不能准确地表达我想要的。

int time = 1;
for (int j = 1; j < timeStamps.size(); j++) {
    if (timeStamps.get(j) - timeStamps.get(j -1) == 1) {
        time++;
    } else {
        System.out.println("CPU time: " + time + " ms");
        time = 1;
        System.out.println("Non-CPU time: " + ((timeStamps.get(j) - timeStamps.get(j-1))-1) + " ms");
    }
}
System.out.println("CPU time: " + time + " ms");