Google OAuth令牌请求返回“invalid_client”：“未授权”

Question

试图让OAuth2谷歌登录工作，这是我的应用程序发出的原始请求：

client_secret:A1B2C3D4E5F6G7H8I9J0K1L2M

code:1/A1B2C3D4E5F6G7H8I9J0K1L2M3N4O5P6Q7R8S9T0U1V

grant_type:authorization_code

redirect_uri:http://localhost:5000/callback/google/

这是回应：

状态:401未经授权

{
    "error": "invalid_client",
    "error_description": "Unauthorized"
}

null

对此的帮助将不胜感激。我试图在我的应用程序中设置OAuth2支持的“用X登录”功能，已经让脸书和推特没有问题地工作，也想让谷歌工作，但如果我不能解决这个问题，我恐怕我将不得不放弃谷歌Auth。

Answer 1

无效客户端意味着您正在使用的客户端id或客户端机密无效。它们必须是你从谷歌开发者控制台下载的。

提示：您可能需要考虑使用Google python客户机库，它可以帮您完成所有繁重的任务。

from __future__ import print_function
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request

# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/drive.metadata.readonly']

def main():
    """Shows basic usage of the Drive v3 API.
    Prints the names and ids of the first 10 files the user has access to.
    """
    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server(port=0)
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('drive', 'v3', credentials=creds)

    # Call the Drive v3 API
    results = service.files().list(
        pageSize=10, fields="nextPageToken, files(id, name)").execute()
    items = results.get('files', [])

    if not items:
        print('No files found.')
    else:
        print('Files:')
        for item in items:
            print(u'{0} ({1})'.format(item['name'], item['id']))

if __name__ == '__main__':
    main()