增加数组和长度

Question

我尝试过创建循环，比如减去用户想要购买的物品的数量，同时计算取值时的模数为0，减去用户购买的数量，但我离它还很远。

数组来自其他方法：

price[i]是商品的价格BuyItems[i]是用户购买的商品数量包[i]是用户对折扣的选择，例如，用户可以将折扣设置为2包、3包甚至无。

public static void checkOuts(String [] names, double [] price,double [] packs,double addDiscount[], double[] buyItems, double[]addDiscountrate, int k ){

    double orgSub=0;
    double newSub=0;
    double addPercent=0;
    double specDis =0;
    double freePack=0;
    double disCheck =0;
    double count=0;

    for (int i =0; i < k; i++ ) {
        orgSub+=price[i]*buyItems[i];
    }

    System.out.println("Original Subtotal:             $" + orgSub);

for (int i =0; i < k; i++ ) {
    orgSub+=price[i]*buyItems[i];
}

System.out.println("Original Subtotal:             $" + orgSub);

for (int j = 0; j < buyItems.length; j++) {
    disCheck = buyItems[j];

    for(int d =0; d < buyItems.length; d++) {
        freePack = packs[d];

        for (int s =1; s < disCheck; s++)
            if (s % freePack==0) {
                count++;
                disCheck = disCheck -1;
                System.out.println(disCheck);
            }

    }
    specDis+= count*price[j];
    // the final discount that will be subtracted from original
}

Answer 1

我版本的代码（我删除了从未解释过的内容）：

public static void checkOuts(String[] names, double[] price, int[] packs, int[] buyItems) {

        System.out.println("Name\tnumFree\ttotalNum\tTotalPrice");
        for (int i = 0; i < names.length; i++) {
            int numFree = buyItems[i] / (packs[i] + 1);
            double totalPrice = (buyItems[i] - numFree) * price[i];
            System.out.println(names[i] + "\t" + numFree + "\t" + buyItems[i] + "\t\t" + totalPrice);
        }

    }

当使用以下代码调用时：

String[] names = {"Coke", "Pepsi"};
double[] price = {1, 1};
int[] packs = {3, 4};
int[] buyItems = {10, 20};

checkOuts(names, price, packs, buyItems);

您将得到以下输出：（这与您的评论一致）

Name    numFree totalNum TotalPrice
Coke    2       10       8.0
Pepsi   4       20       16.0