Spring WebClient：在请求正文中传递用户名和密码以获取令牌

Question

在这里的Spring WebClient教程之后，我将尝试将请求正文中的用户名和密码（无基本身份验证）传递给APIendpoint，因为它期望这些参数。

我在Postman中进行了测试，在正文中提供用户名和密码作为单独的字段，并将contentType设置为application/x-www-form-urlencoded。这会得到预期的令牌，但是当我使用WebClient实现打印下面的响应时，它会打印：

{"error":"invalid_request","error_description":"Missing form parameter: grant_type"}

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TcpClient tcpClient = TcpClient.create().option(ChannelOption.CONNECT_TIMEOUT_MILLIS, CONNECTION_TIMEOUT_MILIS)
                .doOnConnected(connection -> {
                    connection.addHandlerLast(new ReadTimeoutHandler(CONNECTION_TIMEOUT_MILIS, TimeUnit.MILLISECONDS));
                    connection.addHandlerLast(new WriteTimeoutHandler(CONNECTION_TIMEOUT_MILIS, TimeUnit.MILLISECONDS));
                });

        WebClient client = WebClient.builder().baseUrl(BASE_URL)
                .defaultHeader(HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_FORM_URLENCODED_VALUE)
                .clientConnector(new ReactorClientHttpConnector(HttpClient.from(tcpClient))).build();           


        LinkedMultiValueMap<String, String> multiMap = new LinkedMultiValueMap<>();

        multiMap.add("username", username);
        multiMap.add("password", password);

        BodyInserter<MultiValueMap<String, Object>, ClientHttpRequest> inserter = BodyInserters.fromMultipartData(multiMap);


        WebClient.RequestHeadersSpec<?> request = client.post().uri(API_CALL_GET_TOKEN).body(inserter);


        String response = request.exchange().block().bodyToMono(String.class).block();
        System.out.println(response);

Answer 1

提供。接受（MediaType。APPLICATION_JSON）提供了响应：

WebClient client = WebClient.create();

LinkedMultiValueMap<String, String> credentials = new LinkedMultiValueMap<>();

credentials.add("username", username);
credentials.add("password", password);

String response = client.post()
      .uri(BASE_URL + API_CALL_GET_TOKEN)
      .contentType(MediaType.APPLICATION_FORM_URLENCODED)
      .accept(MediaType.APPLICATION_JSON)
      .body(BodyInserters.fromFormData(credentials))
      .retrieve()
      .bodyToMono(String.class)
      .block();

return response;