JavaSpring Boot-如何从Catch Block获取异常代码

Question

像这样的东西-

  try {
    } catch(Exception e) {
       if(e.statusCode == "Unauthorized") {
          throw new Exception(errorCode, errorMessage)
       }
    }

任何帮助都将不胜感激。寻找简单的解决方案。

Answer 1

由于您正在使用RestTemboard进行HTTP调用，下面的代码应该可以工作

try {
  ResponseEntity<String> response = restTemplate.exchange(endPoints, HttpMethod.GET, httpEntity, String.class); json = mapper.readTree(response.getBody().toString()); 
} catch (HttpClientErrorException e) {
    HttpStatus status = e.getStatusCode();
    if (status == HttpStatus.UNAUTHORIZED) {
         throw new Exception(status,e);
     }
 }